Answer:
The solution code is written in Python.
- def mult2_diff(lst):
- num_list = []
-
- for x in lst:
- num_list.append(x * 2)
-
- diff = num_list[0]
- for i in range(1, len(num_list)):
- diff = diff - num_list[i]
-
- print(diff)
Explanation:
Firstly, based on the requirement stated in the question, define a function <em>mult2_diff() </em>that takes one argument, <em>lst</em>, which is a list of numbers (Line 1).
This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers. Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, <em>lst</em>, and multiply each of them by two and add it to the <em>num_list </em>(Line 4-5).
To attempt the second function task, create another variable, <em>diff</em>, to hold the value of calculated difference between the numbers in the <em>num_list</em>. Initialize <em>diff </em>with the first number in the <em>num_list</em>. Use a another for-loop to traverse through each number in the num_list starting with second index, <em>1</em>, and calculate the difference between the <em>diff </em>and the current number extracted from the <em>num_list </em>through indexing.
At last print the output of <em>diff</em> (Line 11).
Answer:
i think real time fluid dynamics
Explanation:
V
JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ
Answer:
Awww what happened? Sometimes its hard for me to keep a promise.
Explanation:
Answer:
Following are the code block in the Java Programming Language.
//define recursive function
public static long exponentiation(long x, int n) {
//check the integer variable is equal to the 0.
if (x == 0) {
//then, return 1
return 1;
}
//Otherwise, set else
else {
//set long data type variable
long q = exponentiation(x, n/2);
q *= q;
//check if the remainder is 1
if (n % 2 == 1) {
q *= x;
}
//return the variable
return q;
}
}
Explanation:
<u>Following are the description of the code block</u>.
- Firstly, we define the long data type recursive function.
- Then, set the if conditional statement and return the value 1.
- Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
- Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.
