The simplest way is to make for loop first you need to<span> generate 1,2,4,8,16,32,64,128,256....and others number in Array. Then you will check every number. Like this.</span>
<span>Decimal </span>Input 84;
64 is closest to 84.
84-64=20
<span>Write: </span>1
20-32=-12(Because It's negative you will write 0)
Write:10
20-16=4
<span>Write: </span>101
4-8=-4 (Negative)
Write:1010
4-4=0
<span>Write: </span>10101
0-2=-2
0-1=-1
<span>Write: </span><span>1010100 = 84</span>
Answer:
11,424,400 possible passwords
Explanation:
Since all characters are letters and only lowercase
we have 26∧4 = 456,976 possibilities
For a 5-character password which is still lower case sensitive.
we have 26∧5 = 11,881,376 possibilities
Many more possible passwords = (11881376-456976)
= 11,424,400 possible passwords
It is known as the File Transfer Protocol or FTP. It is based on a customer server demonstrate design and uses isolate control and information associations between the customer and the server. FTP clients may conform themselves with an unmistakable content sign-in convention, regularly as a username and secret word, yet can interface namelessly if the server is designed to permit it.
"<span>How can we keep technology alive?" It will always stay alive
"</span><span>What is the history of educational technology?" Once The University of Pennsylvania made the first computer
"</span><span>What are the benefits of using technology for teaching and learning?" It is easier to do homework, turn in homework, do course recovery, and easier to check your grades.
"How will it benefit children in the future?" Same way it does now, and even more.
</span>
Answer:
Explanation:
Let's do this in Python, first we need to convert the number into string in order to break it into a list of character, then we can replace the kth character with d. Finally we join all characters together, convert it to integer then output it
def setKthDigit(n, k, d):
n_string = str(n)
d_char = str(d)
n_char = [c for c in n_string]
n_char[k] = d_char
new_n_string = ''.join(n_char)
return int(new_n_string)
