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KATRIN_1 [288]
3 years ago
10

Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each

of them weigh
Mathematics
1 answer:
Alinara [238K]3 years ago
4 0
The answer is:
Justin weighs 165 pounds.
Greg weighs 180 pounds.


If:
j - Justin's weight
g - Greg's weight

Then the system of equations is:
j + 15 = g              ⇒ g = j + 15
1/2g = j - 75          ⇒ j = 1/2g + 75

We can replace j in the first equation:
g = <span>1/2g + 75 + 15
g - 1/2g = 90
1/2g = 90
</span>⇒ g = 90 ÷ 1/2 = 180
<span>
Thus, Greg weighs 180 pounds.

Now, using the first equation, we will calculate Justin's weight:
</span>j + 15 = g                    ⇒ j = g - 15
g = 180

Thus 
<span>j = g - 15 = 180 - 15 = 165
</span>
Therefore, <span>Justin weighs 165 pounds.</span>
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The 90% confidence interval would be given by (60.09;69.91)    

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Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=11-1=10

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that t_{\alpha/2}=1.81

Now we have everything in order to replace into formula (1):

65-1.81\frac{9}{\sqrt{11}}=60.09    

65+1.81\frac{9}{\sqrt{11}}=69.91

So on this case the 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

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