Answer:
Step-by-step explanation:
Area of the figure = Area of rectangle with dimensions 16 in and 4 in + Area of two right triangles with base (7 - 4 = 3) 3 in and height 8 in

Answer:
L.C.M of 432 and 486: 3888
H.C.F of 432 and 486: 54
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
I'm not entirely sure abt this but here goes nothing
75.36 divided by 3.14 = 24
24 = diameter
radius = 12
We can use the SSS congruence theorem to prove that the two triangles in the attached figure are congruent. The SSS or side-side-side theorem states that each side in the first triangle must have the same measurement or must be congruent on each of the opposite side of another triangle. In this problem, for the first triangle, we have sides AC, CM, AM while in the second triangle we have sides BC, CM, and BM. By SSS congruent theorem, we have the congruent side as below:
AC = BC
CM = CM
AM = BM
The answer is SSS theorem.
Answer:
3/8 or 37.5
Step-by-step explanation:
60/160 simplified