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3 years ago

If Qr=58 and pq=13 find pr

Mathematics

1 answer:

Oksanka [162]3 years ago

6 0

Answer:

PR=71

Step-by-step explanation:

visualize:

P Q R

O-------------O-------------O

13 58

so if PQ + QR = PR, than 13+58=PR

13+58=71

PR=71

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Julie and Eric row their boat (at a constant speed) 18 miles downstream for 3 hours helped by the current. Rowing at the same ra

Nastasia [14]

Answer

Find out the the rate of the boat in still water.

To proof

let us assume that the speed of the boat in the still water = u

let us assume that the speed of the current = v

Formula

$speed = \frac{Distance}{time}$

As given

18 miles downstream for 3 hours

Now for the downstream

$u + v = \frac{18}{3}$

u + v = 6

now for the upstream

As given

the trip back against the current takes 6 hours

$u - v = \frac{18}{6}$

u-v = 3

Than the two equation becomes

u + v = 6 and u - v = 3

add both the above equation

we get

2u = 9

u = 4.5miles per hour

put this in the u - v = 3

4.5 -v = 3

v =1.5 miles per hour

The rate of the boat in the still water is 4.5miles per hour .

Hence proved

3 0

3 years ago

Maths help please! Volume = ?

qwelly [4]

Answer:

9m^3

Step-by-step explanation:

Seperate the shape to two shapes. Two rectangles.

Volume of the bottom rectangle：3X2X1=6

Volume of the top rectangle：1X1.5X2=3

6+3=9

3 0

3 years ago

Brianna and let kelci are raising money for a class field trip. Brianna has raised 3 times more money than kelci, but together t

ddd [48]

Let $x be the amount of money which Kelci has raised. Brianna has raised 3 times more money than kelci, then she has raised $3x. Totally both have aised $(x+3x)=$4x.

Since together they have raised more than $300, then 4x>300,

$x\ \textgreater \ \dfrac{300}{4}$ .
Answer: the inequality $x\ \textgreater \ \dfrac{300}{4}$ can be used to determine the amount of money kelci has raised

7 0

4 years ago

Solve the simultaneous equation: x-y=2

kakasveta [241]

Answer:

Y= –7.08, 5.08

Step-by-step explanation:

hope ya ready bro.

X=36/Y

replace 36/y instead of X

36/Y–Y=2===> 36–Y²=2Y===> Y²+2Y–36=0

Y1= –1+√37≈ –7.08

Y2= –1–√37≈ 5.08

5 0

3 years ago

Consider the following sample set of scores. Assume these scores are from a discrete distribution. 21 29 32 38 38 45 50 64 72 10

ASHA 777 [7]

Answer:

Original data: 21 29 32 38 38 45 50 64 72 100

$\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9$

Mode =38.

$Median = \frac{38+45}{2}=41.5$

Change 1: 2 29 32 38 38 45 50 64 72 100

$\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47$

Mode =38.

$Median = \frac{38+45}{2}=41.5$

Change 2: 29 32 38 38 45 50 64 72 100

$\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52$

Mode =38.

$Median = 45$

Step-by-step explanation:

Original data: 21 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{10} X_i}{10}$

And if we replace we got:

$\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9$

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

$Median = \frac{38+45}{2}=41.5$

Change 1: 2 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{10} X_i}{10}$

And if we replace we got:

$\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47$

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

$Median = \frac{38+45}{2}=41.5$

Change 2: 29 32 38 38 45 50 64 72 100

Now the sample size is 9 instead of 10

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{9} X_i}{9}$

And if we replace we got:

$\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52$

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have odd number of points the median is calculated from the 5 position of the dataset ordered.

$Median = 45$

7 0

4 years ago