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3 years ago

Please help answer ASAP

Mathematics

1 answer:

saul85 [17]3 years ago

6 0

Net profit is how much u would make from doing such a thing.

Since James Hardware sells them for $74.99, and pays $32.55, we can set up an equation based on all options given.

$74.99-$32.55-$22.00-7.56= net profit.
$74.99-$62.11=$12.88
James Hardware's net profit is $12.88 (option D)

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Write the equation of a line that passes through the point (3, 4) and has a slope of -1

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3 years ago

Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is viable solutio

madam [21]

Let's say the number of days library book is late is X, and the total fee is Y.

Liability charges $0.30 dollars as a fee for being 1 day late,

For being 1 day late, fee charge is: 1* $0.30

So, for X days the charge would be: X*$0.30.

Total charge for being X days late is Y, Which means: Y= 0.30 * X.

Now We would have to check all the viable solutions in the answer to see if they satisfy the equation Y= 0.30 * X

Option one(-3, -0.9) and two (-2.5, -0.75) Would not be a viable solution because the value of number of days can not be negative and in option one and two, value of days -3 and -2.5 is negative.

Option three(4.5, 1.35) can not be correct because library charges fee for a full day so the number for days would be a whole number. Library would not charge for 4.5 days, they would either charge of 4 days or 5 days because 4.5 is not an whole number.

Option four(8, 2.40) is the correct answer because it satisfies our equation;

Y= 0.30 * X

2.40= 0.30 * 8

2.40 = 2.40.

Fourth option (8, 2.40) is the only viable solution to this question.

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8 0

3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

aleksklad [387]

Answer:

Speed of Chris Huber = 30.726 m/s

Time taken by Sam = 5.55 s

Step-by-step explanation:

Given:

Distance = 200 m

Time taken by Chris Huber = 6.509 s

Now,

Speed of Chris Huber = $\frac{\textup{Distance}}{\textup{Time}}$

Speed of Chris Huber = $\frac{\textup{200 m}}{\textup{6.509 s}}$

Speed of Chris Huber = 30.726 m/s

Speed of Sam = Speed of Chris Huber + 19.0 km/h

Now,

1 km/hr = 0.277778 m/s

thus,

19.0 km/h = 19.0 × 0.27 = 5.278 m/s

thus,

Speed of Sam = 30.726 + 5.278 = 36.004 m/s

therefore,

Time taken by Sam = $\frac{\textup{Distance}}{\textup{Speed}}$

Time taken by Sam = $\frac{\textup{200}}{\textup{36.004}}$ = 5.55 s

6 0

3 years ago