Answer:
1) f(g(2)) = 24
2) f(g(-1)) = -4
Step-by-step explanation:
1) GIven f(x) = x²+2x and g(x) = 2x
f(g(x)) = f(2x)
f(2x) = (2x)² + 2(2x)
f(2x) = 4x² + 4x
f(g(x)) = 4x² + 4x
f(g(2)) = 4(2)² + 4(2)
f(g(2)) = 16+8
f(g(2)) = 24
2) f(x) = x+1 and g(x) = 5x
f(g(x)) = f(5x)
f(5x)= 5x + 1
f(g(x)) = 5x + 1
f(g(-1)) = 5(-1) + 1
f(g(-1)) = -5+1
f(g(-1)) = -4
Answer:
x ≥ 1
Step-by-step explanation:
Since it's a closed circle x could also be equal to 1. Also, since the arrow is pointing away from 1 the answer of x is greater than 1, therefore the answer is x ≥ 1.
Answer:
substitute that value for x in the polynomial and see if it evaluates to zero
Step-by-step explanation:
A "zero" of a polynomial is a value of the polynomial's variable that make the expression become zero when it is evaluated. As an almost trivial example, consider the polynomial x-3. The value x = 3 is a zero because substituting that value for x makes the expression evaluate as zero.
3 -3 = 0
___
Evaluating polynomials can be done different ways. Straight substitution for the variable is one way. Using synthetic division by x-a (where "a" is the value of interest) is another way. This latter method is completely equivalent to rewriting the polynomial to Horner form for evaluation.
__
In the attachment, Horner Form is shown at the bottom.
Answer:
A)
(Yes. It has a value between zero and one.)
B)
(No. It does not have a value between zero and one.)
C)
. (Yes. It has a value between zero and one.)
D)
(Yes. It has a value between zero and one.)