Answer: the maximal height is 14.75 units of distance.
Step-by-step explanation:
We want to find the maximum height of the function
h(t) = -16*t^2 + 24*t + 5
In order to find the maximum, we need to find the value of t where the derivate of h(t) is equal to zero, then we evaluate our original function in that time.
The derivate of h(t) (or the vertical velocity) is:
h'(t) = 2*(-16)*t + 24 = -32*t + 24
we want to find the value of such:
0 = -32*t +24
32*t = 24
t = 24/32 = 0.75
Now we evaluate our height function in that value.
h(0.75) = -16*0.75^2 + 25*0.75 + 5 = 14.75 units
LCM answers:
1. 28
2. 60
3. 84
The answer is 1/3 or 0.3333
If E is the midpoint, DE and EF are equivalent.
2x+4=3x-1
4=x-1
5=x
Plug the value of x in
2(5)+4
14
3(5)-1
14
14+14=28
Final answer: DE=14, EF=14, DF= 28
The fraction equal to .66 is <span>33⁄50</span>
