Both distances 3966 and 4746 were done in 6 hours, so the speeds are:
speed against wind = 3966/6=661 km/h (difference of airplane and wind)
speed with wind = 4746/6=791 km/h (sum of airplane and wind)
The speed of airplane is greater than that of the wind, so this is a sum and difference problem.
Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
Lesser speed (wind) = (sum-difference)/2 = (791-661)/2 = 65 km/h
Answer:
=24x+3y
Step-by-step explanation:
6(5x+2y)−3(2x+3y)
Distribute:
=(6)(5x)+(6)(2y)+(−3)(2x)+(−3)(3y)
=30x+12y+−6x+−9y
Combine Like Terms:
=30x+12y+−6x+−9y
=(30x+−6x)+(12y+−9y)
=24x+3y
Answer:
<h2>12 </h2>
Step-by-step explanation:
<h2>2.5x = 30</h2><h2>x = 30 / 2.5</h2><h2>x = 12</h2>
Answer:
a
Step-by-step explanation:
Answer:
3.2 units
Step-by-step explanation:
Use the law of sines
z/sin 76 = 2.6/sin 51
z = 2.6 sin 76/sin 51 = 3.2
