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3 years ago

Describe how the transformed function below is obtained from its parent function. y=x^2 4

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

I believe its 4 we haven't really went over it

Mekhanik [1.2K]3 years ago

4 0

<span>D.The parent function is shifted 4 units up.</span> Is your answer

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Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago

I’m a little confused with this? Can someone walk me through this?

mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

the first coordinates of d = (0, 0)

the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal

The distance between the two coordinates = distance of d;

$distance \ between \ two \ coordinates = \sqrt{(x_2-x_1)^2 \ + \ (y_2-y_1)^2} \\\\d = \sqrt{(-3-0)^2 \ + \ (-5-0)^2}\\\\d = \sqrt{9 \ + \ 25} \\\\d = \sqrt{34} \\\\d = 5.83\\\\d = 5.8$

Option A is correct

6 0

3 years ago

Katerina’s digital camera takes low resolution photos that use 0.5 MB of memory, and high resolution photos that use 2.5 MB of m

MissTica

18 high resolution photos
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5 0

3 years ago

How many cylindrical can of bottles 12 cm high and with 6 cm diameter could be filled from a tank containing 125 liters of deter

Orlov [11]

Answer:

368 cans.

Step-by-step explanation:

Volume of 1 can = π r^2 h.

Here h (height) = 12 and r (radius) = 1/2 * 6 = 3 cm.

So V = π * 3^2 * 12

= 108π cm^3.

The tank hold 125 liters

= 125,000 cm^3, so:

Number of cans that could be filled = 125000/ 108 π

= 368.4.

4 0

3 years ago

Read 2 more answers

What is the solution to <img src="https://tex.z-dn.net/?f=-12%5Cgeq%20x-4" id="TexFormula1" title="-12\geq x-4" alt="-12\geq x-4

Murljashka [212]

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4 0

3 years ago