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Artist 52 [7]
3 years ago
5

(4Q) If c < d and x > 1, which of the following must be true?

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Use the rule to change the base

\log_a(b) = \dfrac{\log_c(b)}{\log_c(a)}

To express both logarithms in terms of the natural logarithm (for example, any common base would be fine:

\log_c(x) = \dfrac{\ln(x)}{\ln(c)},\quad \log_d(x) = \dfrac{\ln(x)}{\ln(d)}

Since the natural logarithm is an increasing function, we have

c\ln(d)

which implies

\dfrac{\ln(x)}{\ln(c)}=\log_c(x)

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Helpppppppppppppppppppp
Lelechka [254]

Answer:

30:1

Step-by-step explanation:

1. Look at the graph and follow along the lines.

2. When x is 1 in hours then cakes are 30.

3. So we can write the ratio from cakes to hours.

4. The ratio is 30:1.

5 0
3 years ago
Henry is an avid reader. He devours 90 pages in half an hour. How many pages has Henry read per minute
Sonja [21]

Answer:

you answer is 3 pages per minute

Step-by-step explanation:

devours 90 pages half an hour and so that means in one hour he would devour 180 pages.  

well all you have to do is divide 90 by 30

90/30 = 3


6 0
4 years ago
Read 2 more answers
Tell whether the ordered pair is a solution of the given system. (-2,-4) {y=1/2x -3, y=-2x-8}
kompoz [17]

Answer:

The ordered pair (-2,\, -4) is indeed a solution to the system:

\left\lbrace\begin{aligned} & y = \frac{1}{2}\, x - 3 \\ & y = -2\, x - 8\end{aligned}\right..

Step-by-step explanation:

Consider a system of equations about variables x and y. An ordered pair (x_{0},\, y_{0}) (where x_{0} and y_{0} are constant) is a solution to that system if and only if all equations in that system hold after substituting in x = x_{0} and y = y_{0}.

For the system in this question, (-2,\, -4) would be a solution only if both equations in the system hold after replacing all x in equations of the system with (-2) and all y with (-4).

The \texttt{LHS} of the equation y = (1/2)\, x - 3 would become (-4). The \texttt{RHS} of that equation would become (1/2) \, (-2) - 3. The two sides are indeed equal.

Similarly, the \texttt{LHS} of the equation y = -2\, x - 8 would become (-4). The \texttt{RHS} of that equation would become (-2)\, (-2) - 8. The two sides are indeed equal.

Thus, x = (-2) and y = (-4) simultaneously satisfy both equations of the given system. Therefore, the ordered pair (-2,\, -4) would indeed be a solution to that system.

8 0
2 years ago
If 2^(x+3) - 2x = k(2^x) what is the value of k
svlad2 [7]

Answer:

\large\boxed{C)\ 7}

Step-by-step explanation:

Use:

a^n\cdot a^m=a^{n+m}

2^{x+3}-2^x=2^x\cdot2^3-2^x=8\cdot2^x-2^x=(8-1)\cdot2^x=7\cdot2^x\\\\2^{x+3}-2^x=k(2^x)\\\\7\cdot2^x=k(2^x)\Rightarrow k=7

8\cdot2^x-2^x=8\cdot2^x-1\cdot2^x=(8-1)(2^x)=7\cdot2^x\\\\\text{distributive property:}\ a(b-c)=ab-ac

8 0
3 years ago
HELP ME PLEASE!!! The function f(x) is graphed on the coordinate plane. What is f(−2) ? Enter your answer in the box. f(−2) =
Ksenya-84 [330]

Answer:

f(-2)=-2

Step-by-step explanation:

we know that

x -----> is the independent variable or input value

f(x) ---> is the dependent variable or output value

f(-2) is the value of the function f(x) when the value of x is equal to -2

so

For x=-2

Looking at the graph

f(-2)=-2

For an input value of -2 the output value is -2

5 0
3 years ago
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