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schepotkina [342]
2 years ago
10

The lengths of the hypotenuse and one leg of a right

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
3 0
It’s the C because i did it in virtual class science
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A bag contains 3 blue marbles, 7 red marbles, and 5 yellow marbles. If Joe picks 1 marble from the bag at random, what is the pr
fomenos
You just add all the marbles which is 15 marbles. Then how many blue ones are there 3. So you just do blue out of the whole. So your answer is 3/15
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3 years ago
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2. John earns a 3% commission for every car he sells. Today he sold a car for $13,600. How much commission did he receive? (To f
OlgaM077 [116]

Answer:

$408

Step-by-step explanation:

Find 3% of $13,600:

3 * 13,600 / 100 = $408

7 0
3 years ago
37. Bowling Alley A charges $5 admission and $3.50 per game. Bowling Alley B
sdas [7]

a. The cost for A = 19, and B = 25.

b. The cost for A = 22.25, and B = 25

c. When you want to play more than five games.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

a. How much does it cost to play four games at each bowling alley?

a. 5 + 3.50 × 4 = 19, B is always $25

b. How much does it cost to play five games at each bowling alley?

b. 5 + 3.50 × 5 = 22.25, B is always $25

c. When is it financially more beneficial to bowl at Bowling Alley B?

c. 5 + 3.50 × 6 = 26, six games cost more than $25.

We can see from the solution that for any number of times we will be charged $25 but for less than 5 times the charges of B will be higher than the charges of A.

Therefore a.The cost for A = 19, and B = 25.The cost for A = 22.25, and B = 25 When you want to play more than five games.

To know more about expression follow

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5 0
1 year ago
Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0
3 years ago
If you enter the formula =A2*(1+$A$1) in cell B2 and then copy cell B2 to C2, the numerical result in cell
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It’s is b 121 . Gang gang
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