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2 years ago

Part B please help me

Mathematics

1 answer:

Juliette [100K]2 years ago

8 0

He drinks 0.75 liters of juice each day
or
6/8 liters of juice each day

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A lawn sprinkler sprays water 5 ft in every direction as it rotates. What is the area of the sprinkled lawn?

Karolina [17]

Answer:

78.57

Step-by-step explanation:

Radius is 5 feet

Area of circle is pi*r Squared

22/7*5*5

78.57 square feet

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2 years ago

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How does finding the square root of a number compare to finding the cube root lf a number? Use the number 64 in your explainatio

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If you want to know the concept of square roots and cube roots ?

the square root of a number is that number which when multiplied by itself two times gives us that number

e.g.

√64 = x , so that (x)(x) = 64

and from our multiplication table we know that

(8)(8) = 64 , so that

√64 = 8

the cube root of a number is that number which when multiplied by itself three times gives us that number

e.g.

∛64 = x , so that (x)(x)(x) = 64 , and thus x = 4 because 4x4x4 = 64

so ∛64 = 4

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3 years ago

An open box with a square base is to be made from a square piece of cardboard 24 inches on a side by cutting out a square from e

laila [671]

Answer:

x=4 Inch

Step-by-step explanation:

Length of the Square = 24 Inches

If a Square of Length x cm is cut out from each corner

Length of the Box = 24-x-x=(24-2x) Inches

Width of the Box =24-x-x=(24-2x) Inches

Height of the box = x inches

Volume of a Cuboid = Length X Width X Height

V(x)= x(24-2x)(24-2x)

Simplifying

V(x)=4x(12-x)(12-x)

To determine the value of x at which V is largest, we take the derivative of V(x) and solve for the critical points.

V(x)=4x(12-x)(12-x)

$V^{'}(x)=12(x-12)(x-4)$

Set the derivative equal to zero to obtain the critical points

$V^{'}(x)=12(x-12)(x-4)=0\\Since \: 12\neq 0\\(x-12)(x-4)=0\\x-12=0 \:or\: x-4=0\\x=12 \:or\: x=4$

x cannot be equal to 12 as it divides the length of the square cardboard into exactly two equal parts.

When x=4

V(4)=4*4(12-4)(12-4)=16*8*8=1024 Cubic Inches

When x=4 Inch, the volume, V of the open box is largest.

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The slope of GJ is -1

The product of the slopes of the diagonals is -1

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