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siniylev [52]
3 years ago
13

Part B please help me

Mathematics
1 answer:
Juliette [100K]3 years ago
8 0
He drinks 0.75 liters of juice each day
or
6/8 liters of juice each day
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7300 dollars is placed in an account with an annual interest rate of 7.75%. To the nearest tenth of a year, how long will it tak
ryzh [129]
It will take 55 years for the account value to reach 38200 dollars.
4 0
3 years ago
What is the inverse of the function F(x)=x^2 <br><br> Please help me..
ikadub [295]
Firstly make the f(x) = x and x = y:
x = y^2 
Then solve for y:
√x = y
Hopefully this helps and let me know if you have more questions!
8 0
3 years ago
1/8 + 1/4 ?? Why do I need 20 characters to summit this
abruzzese [7]

Answer:

0.375

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
2 years ago
Select the correct answer.
nydimaria [60]

Answer:

It is CD

Step-by-step explanation:

because 300+200=500, juts times it by 3 and divide

5 0
2 years ago
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