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3 years ago

What fraction is equal to 5/8

Mathematics

2 answers:

tatuchka [14]3 years ago

6 0

0.625 that’s the answer cause u have to divide the top and the bottom

vaieri [72.5K]3 years ago

3 0

Answer: 10/16

Step-by-step explanation:

If you do a big giant one of 2 over 2 and multiply that by 5/8, you would get 10/16

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Does anyone know how to answer this question I'm having a lot of trouble with it?

Helen [10]

Answer:

h = $\frac{2A}{(b+c)}$

Step-by-step explanation:

Formula for the area of a trapezoid is,

Area (A) = $\frac{1}{2}(b+c)h$

Here b and c are the bases and 'h' is the height of the trapezoid.

2A = $2[\frac{1}{2}(b+c)h]$

2A = (b + c)h

$\frac{2A}{(b+c)}=h$

Therefore, formula for the height of the trapezoid will be,

h = $\frac{2A}{(b+c)}$

5 0

2 years ago

PLEASE HELP due soon!I forgot how to do it omg

Flura [38]

Answer:

(3, -3) is correct

Step-by-step explanation:

-4 × 3 = -12. -12 + 9 = -3

8 0

3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$