The rate of change of the distance from the particle to the origin at this instant is 3 units per second.
<h3>What is the rate of change?</h3>
The instantaneous rate of change is the rate of change at a particular instant.
A particle is moving along the curve

The rate of change of y is given as:
dy / dx = 2
by differentiating both sides,

From the question, we have:
(x, y) = (5,24)
Substitute 5 for x and dy / dx = 2

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.
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Log(4k - 5) = log(2k - 1)
log(4k) - log(5) = log(2k) - log(1)
0.6020599913k - 0.6989700043 = 0.3010299957k - 0
0.6020599913k - 0.6989700043 = 0.3010299957k
<u>-0.6020599913k -0.6020599913k</u>
<u>-0.6989700043</u> = <u>-0.3010299957k</u>
-0.3010299957 -0.3010299957
2.321928094 = k
Answer:
x= -2, y = -3
Step-by-step explanation:
1. substitute x = 4+2y in the first equation: 
simplify it : 
2. isolate y in 8 + 5y = -7 --> 5y = -7 - 8 -->
3. solve for y: 5y = -15 --> y = -15/5 --> y= -3
4. solve for x: x = 4 + 2y
x = 4 + 2(-3)
x = 4 + (-6)
x = -2
Answer:
Step-by-step explanation:
<u>XO = YO equal as radius, therefore</u>
∠YOZ is exterior angle of the triangle OXY and equal to sum of non-adjacent interior angles
Arc YZ is 108°
Correct option is B