Volume of a cone is equal to pi*r^2*(h/3)
3.14*5^2*2/3 = 52.36 cubic cm.
Density = mass/volume
6 grams/ 52.36 cm^3= 0.1146
Round to 2 decimal places to get D.0.11 g/cm^3
Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
$1688.26
interest= $188.26
Step-by-step explanation:
Given:
Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).
To find:
The y-coordinate of the midpoint of line segment YZ.
Solution:
Midpoint formula:
The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:
Therefore, the y-coordinate of the midpoint of line segment YZ is -1.
