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Viktor [21]
4 years ago
6

Evaluate -u2v3 when u=4 and v=-2

Mathematics
1 answer:
krek1111 [17]4 years ago
8 0
First lets substitute the values:  -4x2x-2x3

Now lets solve: -4 times 2 is -8. Now -8 times -2 is 16 because a negative times a negative is a positive. The last step is to do 16 times 3 which is forty-eight.

Final Answer: When u=4 and v=-2 the equation is 48.
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