The answer to this question is approximately equal to 57.8
Hello, and this is my own words Periodic trends are specific patterns in the properties of chemical elements that are revealed in the periodic table of elements. Major periodic trends include electronegativity, ionization energy, electron affinity, atomic radii, ionic radius, metallic character, and chemical reactivity.
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If we laid each atom end-to-end, they would reach about 20 times the distance from Earth to the Moon.
<em>Assum</em>e that sand has a density of 2 g/cm³ and consists of units of SiO₂.
<em>V</em> = 1 mm³ × (1cm/10 mm)³ = 1 × 10⁻³ cm³
Mass = 1 × 10⁻³ cm³ × (2 g/1 cm³) = 2 × 10⁻³ g
Moles of SiO₂ = 2 × 10⁻³ g × (1 mol SiO₂/60.08 g SiO₂) = 3 × 10⁻⁵ mol SiO₂
Units of SiO₂ = 3 × 10⁻⁵ mol SiO₂ × (6.022 × 10²³ units SiO₂/1 mol SiO₂)
= 2 × 10¹⁹ units SiO₂
Atoms = 2 × 10⁻¹⁹ units SiO₂ × (3 atoms/1 unit SiO₂) = 6 × 10¹⁹ atoms
<em>Assume</em> that each atom has a diameter of 140 pm. If we laid them end to end, they would stretch for
6 × 10¹⁹ atoms × (140 × 10⁻¹² m/1 atom) = 8 × 10⁹ m = 8 × 10⁶ km
That’s 20 times the distance from Earth to he Moon.
Answer:
#1 You get valid data for one.
#2 Not measuring accurately can have some bad consequences.
#3 If you mix the wrong amount of chemicals you can end up getting yourself or worse other people hurt.
#4 When making food you need to measure the amount of sugar or salt you put into the dish or else your face will be this
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether
![\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20diethyl%20ether%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20diethyl%20ether%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20diethyl%20ether%7D%7D%3D%5Cfrac%7B75.0g%7D%7B74g%2Fmole%7D%3D1.01moles)
As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = ![\frac{26.5}{1}\times 1.01=26.8kJ](https://tex.z-dn.net/?f=%5Cfrac%7B26.5%7D%7B1%7D%5Ctimes%201.01%3D26.8kJ)
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether