Answer:
- <u><em>Ratio of the mass carbon that combines with 1.00 g of oxygen in compound 2 to the mass of carbon that combines with 1.00 g of oxygen in compound 1 = 2</em></u>
Explanation:
First, detemine the mass of oxygen in the two samples by difference:
- mass of oxygen = mass of sample - mass of carbon
Item Compound 1 Compound 2
Sample 80.0 g 80.0 g
Carbon 21.8 g 34.3 g
Oxygen: 80.0 g - 21.8g = 58.2 g 80.0 g - 34.3 g = 45.7 g
Second, determine the ratios of the masses of carbon that combine with 1.00 g of oxygen:
- For each sample, divide the mass of carbon by the mass of oxygen determined above:
Sample Mass of carbon that combines with 1.00 g of oxygen
Compound 1 21.8 g / 58.2 g = 0.375
Compound 2 34.3 g / 45.7 g = 0.751
Third, determine the ratio of the masses of carbon between the two compounds.
- Divide the greater number by the smaller number:
- Ratio = 0.751 / 0.375 = 2.00 which in whole numbers is 2
Answer:
The common ion will be di-positive ion.
Explanation:
The ionization energy is defined as the amount of energy needed for removal of most loosely bound electron from an isolated atom in gaseous state.
The low ionization energy shows that the atom is able to give electron easily as after losing electron it may attain noble gas configuration or half filled stability.
Here the first and second ionization energy, both are low suggesting that the element is ready to give two electrons easily to form a di-positive ion however the third ionization energy is high which shows that it will not form tri-positive ion commonly.
Birds use the magnetic fields and some fish i believe as well and maybe butterflies im not entirely sure <span />
Answer:
The right option is the 4 one. nucleoid
Prokaryotic cells are simple cells that lack a definite nucleus and some membrane-bound organelles. Prokaryotic cells have a nucleoid region, which is an irregularly-shaped central region of the cell that contains the cell’s genetic information (DNA). Other organelles that can be found in prokaryotic cells include plasma membrane, cell wall, cytoplasm, and ribosomes.
Explanation:
