All categories

3 years ago

Please show me step by step: x^3+2x^2-5x-6=0

Mathematics

1 answer:

Kazeer [188]3 years ago

3 0

Answer:

x=-1, x=2, x=3

Step-by-step explanation:

Factor the left side of the equation.

(x+1)(x^2+x-6)

(x+1)(x-2)(x-3)

Now set everything equal to 0

x+1=0

x-2=0

x-3=0

Now solve for x

therefore, the answer is x=-1, x=2, x=3

You might be interested in

Simplify this please (multi choice)

kow [346]

3 2/3 = 3x3=9+2=11/3
4 2/5= 4x5=20+2=22/5

5 0

2 years ago

The volume of a cylinder = ar2h. Use 3.14 for A. What is the volume of this cylinder? You may use the calculator tool in the men

zloy xaker [14]

Answer:

{Height and radius not given}

7 0

2 years ago

What does -(-5) equal/mean?

Andrews [41]

Answer:

it means positive 5. because negative + negative = positive or you can think like -1 times -5 which is 5.

Step-by-step explanation:

6 0

2 years ago

HELPPPPP!!!!!!!!!!!!!!!!!!!

8090 [49]

A trinomial is a polynomial with three terms. It can be determined if it is a difference of two squares when you factor it.

The resulting factor of a trinomial that is a difference of two squares is: a²<span> – b</span>²<span> = (a + b)(a – b) or (a – b)(a + b)</span>

You will notice that the middle term is missing. This means that the middle term zeroes out as a result of having the same number of different signs (+ and -)

5 0

3 years ago

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
$=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2$

8 0

3 years ago