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ollegr [7]
3 years ago
13

Please show me step by step: x^3+2x^2-5x-6=0

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

x=-1, x=2, x=3

Step-by-step explanation:

Factor the left side of the equation.

(x+1)(x^2+x-6)

(x+1)(x-2)(x-3)

Now set everything equal to 0

x+1=0

x-2=0

x-3=0

Now solve for x

therefore, the answer is x=-1, x=2, x=3

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JK and LM are straight lines. Find /NOK.<br> ( help me pls)<br>​
VashaNatasha [74]

Answer:

NOK = 58

Step-by-step explanation:

Given

JOM = 108

LON = 50

Required

Find NOK

From the attached triangle, we have:

LOK = JOM =108 --- Corresponding angles

And

LOK = LON + NOK

Substitute for LOK and LON

108= 50+ NOK

Make NOK the subject

NOK = 108 - 50

NOK = 58

8 0
3 years ago
What is the following sum? 4(5√x^2 y) +3(5√x^2 y)
Levart [38]

the answer is 35 x √ 2 y

3 0
3 years ago
Read 2 more answers
Describe a real life multiplication situation for which an estimate makes sense
Drupady [299]
If you are trying to create a garden of potted plants, you would find out how much soil each pot needs/holds and multiply that by how many pots you plan to use. then you would go to the store for potting soil, which let’s say came in smaller packs and you need to purchase multiple. use multiplication estimation to estimate how many bags you’d need.
I know this is a dumb example...sorry this is one I remember from my fourth grade math teacher ahah
3 0
3 years ago
300 ml of an IV fluid contains 50 mcg of Drug A. If a patient is receiving 1000 ml of this IV fluid, how much of Drug A is this
Harlamova29_29 [7]

Answer: 166.666 mcgs

Step-by-step explanation:

3 0
3 years ago
Describe the graph of the function.y = |x – 4| – 7
juin [17]
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x
Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Hope it helps, despite being this long!
3 0
3 years ago
Read 2 more answers
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