All categories

3 years ago

How do you do #1 & #2 ?

Mathematics

1 answer:

Alexeev081 [22]3 years ago

7 0

$Answer: \\ 1. \: x = \frac{ {32}^{2} }{24} = \frac{128}{3} \\y = \sqrt{ {24}^{2} + {32}^{2} } = 40\\ z = \frac{32 \times 40}{24} = \frac{160}{3} \\ \\ 2. \: x = \sqrt{( {4 \sqrt{5} )}^{2} - {8}^{2} } = 4$

You might be interested in

Solve 2 > -3t - 10<br> Please explain

Delicious77 [7]

<h3>Hello there!</h3>

In this question, we're solving for t in the inequality.

Solve:

2 > -3t - 10

Add 10 to both sides

12 > -3t

Divide both sides by -3, also flipping the inequality since you're dividing by a negative

-4 < t

The t must be in the left side, so we would flip the whole equation.

t > -4

<h3>Answer: t > -4</h3><h3>I hope this helps!</h3><h3>Best regards,</h3><h3>MasterInvestor</h3>

3 0

3 years ago

Read 2 more answers

QUESTION as picture below

iogann1982 [59]

I don’t really know this one but I’m sure someone will help

3 0

3 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago

HELP PLEASE!! Alita is 2 times as old as Jiro. Jiro is 4 years younger than Erik. Erik is 1/3 as old as dawn. The sum of all the

Aleonysh [2.5K]

Answer:

a cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speed

5 0

3 years ago

Read 2 more answers

Please help!! How can I use the values of the discriminant to describe the solutions?

alexdok [17]

I think you are referring to the (square root of b^2 - 4ac) in the quadratic formula.
When b^2 - 4ac is less than zero, the solutions to the quadratic equation will be complex (iamginary).

4 0

3 years ago