Answer:
what is the question?.....
Answer:

Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
We know that the tangents are perpendicular to the radius at the point of contact . And here OLMN is a quadrilateral. Also we know that , the angle sum property a triangle is 360° .
<u>According</u><u> to</u><u> question</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> x</u><u> </u><u>is </u><u>6</u><u>3</u><u>°</u><u> </u><u>.</u>
You can solve for sides of a triangle using the following equation.
A = arccos (b^2 + c^2 - a^2/2bc)
And likewise for other variables by moving the letters.
Ultimately, in this problem you get the following angle measures:
15.87
23.97
140.16
Is there a plot?? How do I know where each point is??
Answer:
D!
Step-by-step explanation: