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qwelly [4]
3 years ago
5

Need a new fresh answer to this question don't copy and paste other peoples work please also will make brainleist

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Answer:

Step-by-step explanation:

if you're trying to find the length of the missing side for the right triangle ABC with sides A=5, B=13, C=? ,

Then you need to solve  A^2+B^2=C^2

-> 5^2+13^2=C^2

-> 25+169=194=C^2

Solve C^2=194 so C=13.93.

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What is 2 to the power of four thirds equal to?
Yanka [14]

Answer:

This is the cube root of 16

Step-by-step explanation:

2 ^ (4/3)

2^4 = 16

16 ^(1/3)

This is the cube root of 16

5 0
3 years ago
Read 2 more answers
Determine the value of f (4) if f (x) = 3x -- 1
sleet_krkn [62]

Answer: 11

Step-by-step explanation: plug in 4 for x

3(4) - 1 = 12 - 1 = 11

4 0
3 years ago
There are 12000 pupils in a school. Find the ratio of the boys to the girls if the number of girl is 650
My name is Ann [436]
227:13, that’s it in its simplest form.
5 0
3 years ago
Find the length of each bolded arc. Round to the nearest hundredth.
Nezavi [6.7K]

Answer:

Length of the bold arc = 72.63 ft

Step-by-step explanation:

Length of the arc = \frac{\theta}{360}(2\pi r)

Here, θ = angle subtended by the arc at the center

r = Radius of the circle

Since, angle subtended by the bold arc at the center = 360 - 73

                                                                                         = 287°

And radius of the circle 'r' = 14.5 ft

By substituting these values in the formula,

Length of the bold arc = \frac{287}{360}\times (2\pi)(14.5)

                                     = 72.632

                                     ≈ 72.63 ft

Therefore, length of the bold arc = 72.63 ft

8 0
3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
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