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qwelly [4]
3 years ago
5

Need a new fresh answer to this question don't copy and paste other peoples work please also will make brainleist

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Answer:

Step-by-step explanation:

if you're trying to find the length of the missing side for the right triangle ABC with sides A=5, B=13, C=? ,

Then you need to solve  A^2+B^2=C^2

-> 5^2+13^2=C^2

-> 25+169=194=C^2

Solve C^2=194 so C=13.93.

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Plz help I don’t know the answer
Rudiy27

Answer:

0.95

Step-by-step explanation:

8-3.25=4.75

4.75÷5=0.95

5 0
3 years ago
Someone please help me with this question !!!!
Lyrx [107]

Answer:

34.3 in, 36.3 in

Step-by-step explanation:

From the question given above, the following data were obtained:

Hypothenus = 50 in

1st leg (L₁) = L

2nd leg (L₂) = 2 + L

Thus, we can obtain the value of L by using the pythagoras theory as follow:

Hypo² = L₁² + L₂²

50² = L² + (2 + L)²

2500 = L² + 4 + 4L + L²

2500 = 2L² + 4L + 4

Rearrange

2L² + 4L + 4 – 2500 = 0

2L² + 4L – 2496 = 0

Coefficient of L² (a) = 2

Coefficient of L (n) = 4

Constant (c) = –2496

L = –b ± √(b² – 4ac) / 2a

L = –4 ± √(4² – 4 × 2 × –2496) / 2 × 2

L = –4 ± √(16 + 19968) / 4

L = –4 ± √(19984) / 4

L = –4 ± 141.36 / 4

L = –4 + 141.36 / 4 or –4 – 141.36 / 4

L = 137.36/ 4 or –145.36 / 4

L = 34.3 or –36.3

Since measurement can not be negative, the value of L is 34.3 in

Finally, we shall determine the lengths of the legs of the right triangle. This is illustrated below:

1st leg (L₁) = L

L = 34.4

1st leg (L₁) = 34.3 in

2nd leg (L₂) = 2 + L

L = 34.4

2nd leg (L₂) = 2 + 34.3

2nd leg (L₂) = 36.3 in

Therefore, the lengths of the legs of the right triangle are 34.3 in, 36.3 in

5 0
3 years ago
if you solve this with the steps your littearly such a pro pro pro pro pro pro pro pro pro pro prohacker​
Yuri [45]

Answer:

maybe 1.5 songs per minute

8 0
2 years ago
Read 2 more answers
Steps to solving y=2x+3 x=y-8
tatuchka [14]
First, plug in x=y-8 to y=2x+3
Next, it would be y=2(y-8)+3
Then, you need to distribute: y= 2y-16+3
After that, move 2y to the other side: -y= -13 (notice I also did -16+3)
Finally, divide negatives into both sides: y=13

Now to find x just plug in 13 to either of the equations: 13=2x+3
Then solve: x=5
So the FINAL answer is: (5,13)
Hope this helps!!!!!!!

3 0
3 years ago
Find the equation of the line that passes through (-1,2)and is perpendicular to 2y=x-3
Umnica [9.8K]
Sorry I don’t have roller
Hope it’s right
Best luck with your studying

4 0
2 years ago
Read 2 more answers
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