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3 years ago

Geometry Help I can't figure this out and it's stressing me out

Mathematics

1 answer:

stiv31 [10]3 years ago

5 0

Answer:

Reason 3: Definition of sine.

Reason 4: Multiplication property of equality

Reason 6: Division property of equality

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What is -2(-y) in expanded form

damaskus [11]

Answer:

Step-by-step explanation:

$(-2)(-y) = (-1)(2)(-1)(y) = (-1)^2\ccdot 2y = 2y$

4 0

2 years ago

Cual es el valor de un esfero cuando la docena se compra en $7848? Area de un triangulo de 9 unidades de base y 6 unidades de al

aniked [119]

Answer:

a) $654

b) 27 unidades cuadradas

c) 721

Step-by-step explanation:

a) ¿Cuál es el valor de un bolígrafo cuando la docena se compra por $ 7848?

Una docena = 12

Por eso:

12 bolígrafos = $ 7848

1 bolígrafo = $ x

Cruz multiplicar

12 bolígrafos × $ x = 1 bolígrafo × $ 7848

$ x = 1 bolígrafo × $ 7848/12

$ x = $654

b) Área de un triángulo ¿9 unidades de base y 6 unidades de altura?

Área de un triángulo =

= 1/2 × Base × Altura

1/2 × 9 × 6

= 27 unidades cuadradas

c) Cien veces la suma de 4.5 con 2.71

Esto se calcula como:

100 × (4,5 + 2,71)

= 100 × (7.21)

= 721

6 0

2 years ago

Point Lis a centroid of the triangle FWD, If RL = 54 cm, what is RD?

Wittaler [7]

Answer:

RD = 162 cm

Step-by-step explanation:

LD = 2 RL = 2* 54 = 108

RD = RL + LD

RD = 54 + 108

RD = 162 cm

7 0

3 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Help me please i need this now

ICE Princess25 [194]

Answer:

210?

Step-by-step explanation:

Sorry if it's wrong

4 0

3 years ago