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forsale [732]
3 years ago
8

Two right triangles that are not similar still may have one congruent acute angle in common

Mathematics
2 answers:
krok68 [10]3 years ago
8 0

Answer: false -apex 2019

AnnZ [28]3 years ago
3 0

False.

Any two right triangles, similar or not, must have one pair of congruent angles, the right angles.

If one pair of acute angles angles is congruent, then by AA Similarity, the triangles are similar.

Therefore, for two right triangles to not be similar, neither of the acute angles of one triangle may be congruent to an acute angle of the other triangle

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Yes because if you simplify 24 and 4 weeks(28 days) by 2 than you would get 12 and 2 weeks(14 days)
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Which equation is satisfied by all of the plotted points?
Brums [2.3K]
The equation that is satisfied by all of the plotted points would be F. 3x because the y-intercept is at 0 so there wouldn't be one and the graph has a ratio of 3/1 so for every 3 numbers the line moves up it moves 1 space to the right, also indicating that it is positive.
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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol
kobusy [5.1K]

Answer:

15.2\ units

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

P=AB+BC+CD+DE+AE

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 2

<em>Find the distance AB</em>

A(-2, 1). B(-3, 3)

substitute in the formula

d=\sqrt{(3-1)^{2}+(-3+2)^{2}}

d=\sqrt{(2)^{2}+(-1)^{2}}

d_A_B=\sqrt{5}=2.24\ units

step 3

<em>Find the distance BC</em>

B(-3, 3), C(-1, 5)

substitute in the formula

d=\sqrt{(5-3)^{2}+(-1+3)^{2}}

d=\sqrt{(2)^{2}+(2)^{2}}

d_B_C=\sqrt{8}=2.83\ units

step 4

<em>Find the distance CD</em>

C(-1, 5), D(2, 4)

substitute in the formula

d=\sqrt{(4-5)^{2}+(2+1)^{2}}

d=\sqrt{(-1)^{2}+(3)^{2}}

d_C_D=\sqrt{10}=3.16\ units

step 5

<em>Find the distance DE</em>

D(2, 4),E(2, 1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(2-2)^{2}}

d=\sqrt{(-3)^{2}+(0)^{2}}

d_D_E=\sqrt{9}\ units

d_D_E=3\ units

step 6

<em>Find the distance AE</em>

A(-2, 1).E(2, 1)

substitute in the formula

d=\sqrt{(1-1)^{2}+(2+2)^{2}}

d=\sqrt{(0)^{2}+(4)^{2}}

d_A_E=\sqrt{16}\ units

d_A_E=4\ units

step 7

Find the perimeter

P=AB+BC+CD+DE+AE

substitute the values

P=2.24+2.83+3.16+3+4=15.23\ units

Round to the nearest tenth of a unit

P=15.2\ units

6 0
3 years ago
Just having lil problem with this math problem if anyone can help me please solving. thanks
Cloud [144]
1-2 is right
3 you have to draw a shape and then put 3 lines then shade in one
number 4 you have to draw a shape again but put 8 lines through then shade 1
5 your answer is 1/8
6 your answer is 1/4
7 you have to draw a shape again draw 3 line in the shape then shade 1 and your fraction is 1/3
7 0
3 years ago
On my brother's 14th birthday, he was 160 cm tall. Within exactly one year, his height increased by 6%. How tall was he on his 1
Charra [1.4K]

Answer:

170 cm

Step-by-step explanation:

160+.06*160=160+9.6=169.6

8 0
3 years ago
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