Answer:
Step-by-step explanation:
2. area of a triangle is 1/2 b h
1/2 (5 * 2) = 5 yd squared
area of the circle is pi r squared
you only need 1/2 of this area
find all these areas and add them together.
6. this is just a square sitting on a rectangle.
36 x 36 for the square
36 x 60 for the rectangle
add these together.
8. this a 1/2 circle and a triangle.
area of a circle is pi r squared
r is 7 in this problem
the area of a triangle is 1/2 b h
height is 7x2 here or 14
add the two together.
The angles and length of the triangle area as follows:
- ∠CBD = 61°
- ∠A = 35°
- AD = 32.77 units
- BD = 22.94 units
- BC = 11.12 units
- CD = 9.73 units
<h3>How to find the sides and angle of a triangle?</h3>
The sum of angles in a triangle is 180 degree.
Therefore,
∠DBC = 180 - 29 - 90 = 61°
Hence,
∠A = 180 - 29 - 61 - 55 = 35°
∠CBD = 61°
Using trigonometric ratios,
sin 55 = opposite / hypotenuse
sin 55 = AD / 40
AD = 40 sin 55
AD = 32.7660817716
AD = 32.77 units
cos 55 = adjacent / hypotenuse
cos 55 = BD / 40
BD = 40 cos 55
BD = 22.943057454
BD = 22.94 units
sin 29 = 22.94 / BC
BC = 22.94 sin 29
BC = 11.1215326885
BC = 11.12 units
cos 29 = CD / 11.12
CD = 11.12 cos 29
CD = 9.72577114339
CD = 9.73 units
learn more on triangle here: brainly.com/question/17307037
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I believe the answer is .001
.4 x .25 = .1
.1 x .01 = .001
Assuming ballistic motion, the equation for height as a function of time is
h(t) = -16t² + v0·t + h0
where v0 is the initial vertical velocity (44 ft/s) and h0 is the initial height (8 ft).
You want to find t such that h(t) = 15. Substituting the given values, we have
15 = -16t² +44t +8
16t² -44t +7 = 0
Using the quadratic formula, we find t to be ...
t = (44 ±√(44² - 4·16·7))/(2·16)
t = (11 ± √93)/8
We are not interested in the time when the football is rising through the 15 ft height, so the time of interest is
t = (11 +√93)/8 ≈
2.580 . . . . seconds
Answer:
50π ≈ 157.08 cubic units
Step-by-step explanation:
The volume of revolution of a plane figure is the product of the area of the figure and the length of the path of revolution of the centroid of that area. The centroid of a triangle is 1/3 the distance from each side to the opposite vertex. (It is the intersection of medians.)
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<h3>length of centroid path</h3>
One side of this triangle is the axis of revolution. Then the radius to the centroid is 1/3 the x-dimension of the triangle, so is 5/3. Then the circumference of the circle along which the centroid is revolved is ...
C = 2πr
C = 2π(5/3) = 10π/3 . . . units
<h3>triangle area</h3>
The area of the triangle is found using the formula ...
A = 1/2bh
A = 1/2(5)(6) = 15 . . . square units
<h3>volume</h3>
The volume is the product of the area and the path length:
V = AC
V = (15)(10π/3) = 50π . . . cubic units
The volume of the solid is 50π ≈ 157.08 cubic units.
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<em>Additional comment</em>
In the attached figure, the point labeled D is the centroid of the triangle. The label has no significance other than being the next after A, B, C were used to label the vertices.
The volume of revolution can also be found using integration and "shell" or "disc" differential volumes. The result is the same.