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attashe74 [19]
3 years ago
13

Which would you consider to be more accurate, a probability experiment of 10 trials or a probability experiment of 100 trials

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
I would 100 because the more the trials means the more the results which means you get more of an accurate experiment then if you only did 10. Because since you have so many answers from all of the experiments you can conclude the correct answer from all of the experiments. I hope you get what I’m trying to say
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Write 3.141 in expanded notation
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Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
What are the solutions to. x^2 - x - 20 = 0
nignag [31]

Step-by-step explanation:

<em>x² - x - 20 = 0</em>

<em>x²</em><em> </em><em>-</em><em> </em><em>(</em><em>5</em><em>-</em><em>4</em><em>)</em><em> </em><em>x </em><em>-</em><em> </em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x²</em><em> </em><em>-</em><em> </em><em>5x </em><em>+</em><em> </em><em>4x </em><em>-</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>(</em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>(</em><em>x+</em><em> </em><em>4)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>Either</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>x </em><em>-</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>=</em><em> </em><em>5</em>

<em>Or, </em>

<em>x </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x </em><em>=</em><em> </em><em>-</em><em>4</em>

3 0
3 years ago
PLEASE HELP!!!!<br><br> IT'S NOT B<br><br> A. 1/4<br> B. 1<br> C. 4<br> D. None of the above
konstantin123 [22]

Answer:

YOUR ANWSER IS C

Step-by-step explanation:

HOPE THIS HELPED

8 0
3 years ago
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