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adelina 88 [10]
3 years ago
6

You are troubleshooting a computer that your client said turns off during normal operation. While you are trying to identify the

problem, the client also informs you that if he waits a while, the computer will turn back on and run normally for a bit. You open the system and immediately notice a large dust buildup around the processor fan and heat sink. What problem can you detect on the computer and confidently report to your client?
Computers and Technology
1 answer:
Scilla [17]3 years ago
7 0

Answer:

In this case, it seems to me as the system is overheating.

Explanation:

The reason why this is the case is because the processor (CPU) needs airflow to constantly cool itself when running tasks. The airflow works by intakes and exhaust fans within the computer case.  Specifically around the processor fan and the heat sink, it is usually designed for exhaust (Some can also be intakes as well). The dust that is collected restricts the fan from properly exhaust all the hot air from the CPU as the dust can be clumped up together. Both the heat sink and the fan are the main components as the air flows through those areas.

Your computer doesn't necessarily just let it burn itself out. It is constantly monitoring the temperatures of the system and if it reaches a limit, it will turn off the system to prevent it from overheating and will turn back on when the temperatures are acceptable to run again.

Have a nice day!

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Write a console-based employee management system through binary File Handling (In order to observe data security, we use binary
dangina [55]

Answer:

#include <fstream>

#include <iostream>

#define FILE_N "employee.dat"

using namespace std;

class Employee {

private :  

int  empID;

char  empName[100] ;

int  salary;

public  :

void readEmployeeDetails(){

 cout<<" PLEASE SUBMIT EMPLOYEE DETAILS"<<endl;

 cout<<"INPUT EMPLOYEE ID : " ;

 cin>>empID;

 cin.ignore(1);

 cout<<"ENTER EMPLOYEE NAME: ";

 cin.getline(empName,100);

 cout<<"ENTER EMPLOYEE SALARY : ";

 cin>>salary;

}

void increasesalary(){

 cout<<" Increment Salary"<<endl;

 cout<<"ENTER INCREMENT SALARY : ";

 int sal;

 cin>>sal;

 salary=salary + sal;

}

void displayEmployee(){

 cout<<"EMP ID: "<<empID<<endl

  <<"EMP NAME: "<<empName<<endl

  <<"SALARY: "<<salary<<endl;

}

};

int main(){

   int options;

   

LOOP:cout<<"Enter the Options:";

   cin>>options;

if(options == 1)

{

Employee emp;

emp.readEmployeeDetails();

fstream file;

file.open(FILE_N,ios::out|ios::binary);

if(!file){

 cout<<"There is an Error found while creating file...\n";

 return -1;

}

 

file.write((char*)&emp,sizeof(emp));

file.close();

cout<<"Date has been saved in the file.\n";

goto LOOP;

}

else if(options == 2)

{

Employee emp;    

fstream file;

file.open(FILE_N,ios::in|ios::binary);

if(!file){

 cout<<"There is an error while opening file...\n";

 return -1;

}

 

if(file.read((char*)&emp,sizeof(emp))){

  cout<<endl<<endl;

  cout<<"Data being discovered from the file..\n";

  emp.displayEmployee();

}

else{

 cout<<"There is an error while reading the file...\n";

 return -1;

}

goto LOOP;

}

else

{

  Employee emp;

emp.increasesalary();

fstream file;

file.open(FILE_N,ios::out|ios::binary);

if(!file){

 cout<<"Error found while creating file...\n";

 return -1;

}

 

file.write((char*)&emp,sizeof(emp));

file.close();

cout<<"Date saved inside the file.\n";

goto LOOP;

}

return 0;

}

Explanation:

The above program is in C++. It creates a class, assign it value, and then work on three option.

1. Press 1 to ADD AN EMPLOYEE.

2. Press 2 to DISPLAY FILE DATA.

3. Press 3 to INCREASE EMPLOYEE SALARY.

Rest is as shown in program.

8 0
4 years ago
What different factors would you consider when deciding whether to implement a catch-up mechanic in a single-player game vs. a m
LuckyWell [14K]

Answer:

2.As the name defines that over-the-shoulder perspective, this is the camera position where the viewer can see the front view of the game, like this position is from the back or from the shoulder’s so the player can easily judge the game and play the game easily. So this position is very popular in the games. Furthermore, if we talk about this position according to the first person, this is the same like you are watching from the player’s eye and this makes the game more attention seeker for the player and also those who are watching the game. Likewise, the second person is not much important in the game because this is not controlled by the player but the second person is focused on the player’s action, so the camera position is much less important for the second person. Similarly, the third person is more important than the second person. The third person usually practical consideration like this makes the situation clearer and easier for the player and draws a very clear picture to everyone.

3.When you are talking about the games and building a very interactive game, then this is very important that the game should have some logic and goals. Without a goal and illogic games not lasts a good thought. Catch up mechanics specifically use to define some kind of rewards and goals in the game that will be helpful for the player. Similarly, the single-player games are more interactive as compared to the multi-player because multi-player involve many other people who will be not accepted easily. I catch up mechanics involved in the single-player then this does not mean that you are giving a chance again to win instead to end the game quickly. While using the AI in games for both types, this will give a much higher interactive level and entertaining level. Not every player can take the difficulty level that can be offered after the AI, but after combining the AI with the catch-up mechanics, the game level becomes higher with every perspective.

:)

4 0
3 years ago
Why does a crane need to rotate/swivel​
Alinara [238K]

Answer:

(hope this helps can I pls have brainlist (crown) ☺️)

Explanation:

Swivel hooks are rigging devices used by overhead crane firms to place loads and allow them to swivel on their x-axis. The issue of cables twisting together when bringing up a load is effectively eliminated. This is especially useful in windy outdoor settings.

Swivel hooks are essential components that overhead crane manufacturers use in a variety of sectors. However, they are only helpful if they are in good working order. Swivel hooks must be inspected regularly and taken out of service if specific load-bearing components. Missing identifying markings, heat damage, or bent, twisted, or otherwise deformed load-bearing components are examples.

4 0
3 years ago
Pls help I will thx and give points
azamat

Answer:

Desktop

Explanation:

A tablet and smartphone dont have enough storage like a desktop, so they would edit very efficiently

5 0
3 years ago
Read 2 more answers
The length of a hailstone sequence is the number of terms it contains. For example, the hailstone sequence in example 1 (5, 16,
11111nata11111 [884]

Answer:

Following are the program to this question:

#include <iostream> //defining header file

using namespace std;

int hailstoneLength(int n) //defining method hailstoneLength

{

int t=1; //defining integer variable assign  

while(n!=1) //define a loop that checks value is not equal to 1

{

if(n%2==0) // check even number condition

{

n=n/2; // divide the value by 2 and store its remainder value in n

t++; //increment value of t by 1.

}

else

{

n=n*3+1; //calculate and hold value in n  

t++; //increment value of t variable by 1  

}

}

return t; //return value

}

int main() //defining main method

{

int n; //defining integer variable

cout<<"Enter any number: "; //print message

cin>> n; //input value

cout<<hailstoneLength(n); //call method and print its value

return 0;

}

Output:

Enter any number: 3

8

Explanation:

Program description can be given as follows:

  • In the given C++ language program an integer method "hailstoneLength", is declared, that accepts an integer variable "n" in its parameter.
  • Inside the method, an integer variable t is declared, that assign a value that is 1, in the next line, a while loop is declared, that uses if block to check even condition if number is even it divide by 2 and increment t variable value by 1.
  • If the number is odd it will multiply the value by 3 and add 1 and increment t by 1 then it will go to if block to check value again. when value of n is not equal to 1 it will return t variable value.
  • In the main method, an integer variable "n" is used that call the method and print its return value.
7 0
3 years ago
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