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Xelga [282]
3 years ago
15

Simplify. (x9y4)(−8xy2)(−7x3)

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0
(x^9y^4)(-8xy^2)(-7x^3) = 56x^{13}y^6
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Omar has 2 2/3 cups pf dough to male dumplings. If he uses 3/16 cup of dough for each dumpling, how many whole dumplings can he
swat32
2 2/3 cups is = 128 teaspoons and 3/16 is = 9 teaspoon. 128÷9=14.22.. so the answer would be 14
3 0
4 years ago
Please answer ASAP! Thank you in advance, and remember to use wash your hands for 1 minute with antibacterial soap!!
Anastasy [175]

Answer: x=80

Step-by-step explanation:

x/8=10

x=8*10

x=80

5 0
3 years ago
Indefinite integral need help pleaseeeeeee
tatiyna
Integrate indefinite integral:
I=\int\frac{dx}{e^{2x}+3e^x+2}dx

Solution:
1. use substitution u=e^x 
=>
du=e^xdx
=>
dx=\frac{du}{e^x}
=>
dx=\frac{du}{u}
=>
I=\int\frac{du}{u(u^2+3u+2)}du
=\int\frac{du}{u(u+2)(u+1)}du
2. decompose into partial fractions
\frac{1}{u(u+2)(u+1)}
=\frac{A}{u}+\frac{B}{u+2}+\frac{C}{u+1}
where A=1/2, B=1/2, C=-1
=\frac{1}{2u}+\frac{1}{2(u+2)}-\frac{1}{u+1}
3. Substitute partial fractions and continue
I=\int\frac{du}{2u}+\int\frac{du}{2(u+2)}-\int\frac{du}{u+1}
=\frac{log(u)}{2}+\frac{log(u+2)}{2}-log(u+1)}
4. back-substitute u=e^x
=\frac{log(e^x)}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}
=\frac{x}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}

Note: log(x) stands for natural log, and NOT log10(x)

7 0
3 years ago
What is the domain of the relation shown?<br> will mark as branliest
Schach [20]

Answer:

2 or 4

Step-by-step explanation:

6 0
3 years ago
I really need help please____________
Lynna [10]

Answer:

P ($1 or $5)  = 5/6

Step-by-step explanation:

There are 6 $1

There are 4 $5

There are 2 $10

There are a total of 12 spaces


P ($1 or $5) = ($1 or $5)/ total

There are 6 ones and 4 fives

                   = (6+4)/ 12

                   = 10/12

Divide the top and bottom by 2

                   =5/6

4 0
4 years ago
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