SOMEONE HELP ME PLSSSSSSS

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer:

y = 8x

Step-by-step explanation:

hope this is what u need if not comment and I'll change it

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if an area can be washed at a rate of 4,900 cm2/ minute, how many square inches can be washed per hour?

Olenka [21]

Answer : 4.5 × 10⁴ square inches can be washed per hour.

Step-by-step explanation :

As we are given that an area can be washed at a rate of 4,900 cm²/min. Now we have to determine the square inches can be washed per hour.

Given conversions are:

1 cm = 0.39 in and 1 hr = 60 min

As, 1 cm² = (0.39)² in² and 1 min = 1/60 hr

So, $1cm^2/min=(0.39)^2\times 60in^2/hr$

$1cm^2/min=9.126in^2/hr$

Now we have to determine the square inches can be washed per hour.

As, $1cm^2/min=9.126in^2/hr$

So, $4900cm^2/min=\frac{4900cm^2/min}{1cm^2/min}\times 9.126in^2/hr=44717.4in^2/hr=4.5\times 10^4in^2/hr$

Therefore, 4.5 × 10⁴ square inches can be washed per hour.

4 0

3 years ago

Help me plsss thanks

Andrews [41]

Answer:

Option A is correct answer

4 0

3 years ago

Read 2 more answers

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .