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amid [387]
3 years ago
9

Is this answer correct?

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

Answer:

No

Step-by-step explanation:

How to solve :

(a-4)/(a^2+8a+12)*(a^2-2a-48)/(a^2+4a-32)

Factor:

a^2+8a+12 = (a+6)(a+2)

a^2-2a-48 = (a-8)(a+6)

a^2+4a-32 = (a+8)(a-4)

simplify a+6, and a-4

you are left with (a-8)/(a+2)(a+8) = (a-8)/(a^2+10x+16)

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\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{s}{s}=\cfrac{\sqrt[3]{8}}{\sqrt[3]{125}}\implies \cfrac{s}{s}=\cfrac{2}{5}\qquad \leftarrow \textit{ratio of the sides or scale factor}

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