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Advocard [28]
3 years ago
8

Find the domain of the graphed function A. 2 2 C. 1<= x <= 5 D. x is all real numbers

Mathematics
1 answer:
Reptile [31]3 years ago
4 0
The answer is 3 that’s not rug I recalling don’t no the answer
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Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system.
FrozenT [24]

Given:

The system of inequalities:

x>3

y

To find:

The point that represents a solution to the system by using the graph.

Solution:

We have,

x>3

y

The related equations of these inequalities are:

x=3

y=2x-5

The line x=3 is a vertical line that intersect the x-axis at 3.

The table of values for y=2x-5 is:

x         y

0       -5

1        -3

Plot (0,-5) and (1,-3) on a coordinate plan and connect them by a straight line.

The boundary lines are dotted lines because the points on the lines are not included in the solution set.

Check the inequalities for (0,0).

First inequality: 0>3           ( False)

Second inequality: 0

                               0     (False)

Both inequalities are false for (0,0). It means the shaded region of the lines is in the opposite direction of (0,0).

Plot the shaded region and the points (-3, -1), (1, 11), (4, -1), (5, 6) as shown in the below graph.

From the below graph, it is clear that the point (4,-1) is the only point lies in the common shaded region. So, (4,-1) represents a solution to the system.

Therefore, the correct option is C.

5 0
3 years ago
Consider the absolute vale function f(x)=-|x+2|-2<br>the vertex of the function is
Ilya [14]
The vertex of the absolute value function f(x) = |x| is (0,0).
What about <span>f(x)=-|x+2|-2?  This can be re-written as f(x) = -|x-(-2)| -2.
Three things happen here:  first, the graph of f(x) = |x| must be inverted, so that it opens down instead of up; second, the resulting graph must be translated 2 units to the left; and third, the resulting graph must be translated 2 units down.
 </span>
4 0
4 years ago
Read 2 more answers
The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
FrozenT [24]

Let Y_i denote the number of packages brought by customer i. If, for instance, X=2 customers are in line, then the total number of packages is Y=Y_1+Y_2, and

P(Y=y)=P(Y_1=y_1,Y_2=y_2)=P(Y_1=y_1)P(Y_2=y_2)

since the number of packages brought by any customer is independent from the number of packages brought by any other.

a. P(X=3,Y=3) is the probability that a total of 3 packages are waiting to get wrapped from among a total of 3 customers. This means each customer must have exactly one package. So

P(X=3,Y=3)=P(X=3)P(Y=3)^3\approx0.0416

b. P(X=4,Y=11) is the probability that a total of 11 packages are brought by 4 customers. The only way for there to be 11 packages is if 3 customers bring 3 packages and the last 1 brings 2. There are \dbinom43=4 ways this can happen, so

P(X=4,Y=11)=4P(X=4)P(Y=3)^3P(Y=2)\approx0.0002

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7Bx-5%7D%7B2x%5E%7B2%7D-5x-3%20%7D" id="TexFormula1" title="f(x) = \f
Vedmedyk [2.9K]

i) The given function is

f(x)=\frac{x-5}{2x^2-5x-3}

The factored form is

f(x)=\frac{x-5}{(x-3)(2x+1)}

The domain are the values of  x for which the function is defined.

(x-3)(2x+1)\ne 0

(x-3)\ne0,(2x+1)\ne 0

x\ne3,x\ne-\frac{1}{2}

ii) To find the vertical asymptotes, equate the denominator to zero.

(x-3)(2x+1)=0

(x-3)=\ne0,(2x+1)=0

x=3,x=-\frac{1}{2}

iii) To find the roots, equate the numerator to zero.

x-5=0

The root is x=5

iv) To find the y-intercept, put x=0 into the function.

f(0)=\frac{0-5}{(0-3)(2(0)+1)}

f(0)=\frac{-5}{(-3)(1)}

f(0)=\frac{5}{3}

The y-intercept is \frac{5}{3}

v) The horizontal asymptote is given by;

lim_{x\to \infty}\frac{x-5}{2x^2-5x-3}=0

The horizontal asymptote is y=0

vi) The function is not reducible. There are no holes.

vii) The given function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

3 0
3 years ago
Read 2 more answers
You have $20 to spend on pizza. It costs $16 plus $1.25 for each additional topping, tax included.
nikdorinn [45]
U only get 1 pizza and prolly 2 toppings
8 0
3 years ago
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