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Zielflug [23.3K]
3 years ago
13

Please help me answer this

Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

option d

Step-by-step explanation:

AB = C

<em>Step 1: Multiply row 1 of matrix B by column 1, 2 and 3 of matrix A to get first column of C</em>

(2x-2)+(3x5)+(-5x-1)     (2x-4)+(3x1)+(-5x-3)      (2x2)+(3x5)+(-5x-4)

= (-4+15-5     -8+3+15     4+15+20)

= (16    10    39)

<em>Step 2: Multiply row 2 of matrix B by column 1, 2 and 3 of matrix A to get second column of C</em>

(5x-2)+(-4x5)+(2x-1)     (5x-4)+(-4x1)+(2x-3)      (5x2)+(-4x5)+(2x-4)

= (-10-20-2     -20-4-6    10-20-8)

= (-32   -30   -18)

<em>Step 3: Multiply row 3 of matrix B by column 1, 2 and 3 of matrix A to get third column of C</em>

(-1x-2)+(-1x5)+(3x-1)     (-1x-4)+(-1x1)+(3x-3)      (-1x2)+(-1x5)+(3x-4)

= (2-5-3      4-1-9     -2-5-12)

= (-6      -6     -19)

<em>Step 4: Form the whole matrix</em>

(16        10    39)

(-32   -30    -18 )

(-6      -6     -19 )

Therefore, option d is correct.

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Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

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green: \frac{2}{14}

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Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

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From the question, we have:

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