Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( > 
) = P(Z > 1.25) = 1 - P(Z 
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Given:
and 
where 
.
To find:
The explicit formula for the given recursive formula.
Solution:
We know that recursive formula of an AP is:
Where, d is the common difference.
We have,
Here, d=9.
The first term of the AP is .
The explicit formula for an AP is:
Substituting and 
, we get
Therefore, the required explicit formula for the given sequence is .
Answer:
B. 1/2
Step-by-step explanation:
You can see that when two weeks that pass, the plant grows one inch. This rate can be written as 1 inch : 2 weeks. But, we need to find the unit rate. To find the unit rate, or how many inches the plant grows per week, we divide both by 2.
1/2 inch : 1 week
1/2
I Hope That This Helps! :)
Answer:
35
Step-by-step explanation:
the pattern is +2 so the answer is 35
