A non-conservative force acting on a particle:_________.

Chemistry

1 answer:

Tpy6a [65]3 years ago

3 0

Answer: Option A.

does work that can depend on the path of motion.

Explanation:

A non-conservative force acting on a particle does work that can depend on the path of motion because a non conservative force is a type of force that can remove energy from a progressive system and this energy cannot be restored back and the forces are path dependent because it matters where the particle begin or end.

It is a type of force such as friction or air resistance. This type of force does work that only depend on the path of motion.

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Need help setting the problem up

Sveta_85 [38]

Answer:

4.0 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 12L

Pressure = 5.6 atm

Temperature (T) = 205K

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

PV = nRT

5.6 x 12 = n x 0.08206 x 205

Divide both side by 0.08206 x 205

n = (5.6 x 12)/(0.08206 x 205)

n = 4.0 moles

Therefore, the number of mole of the gas is 4.0 moles

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3 years ago

Under what conditions are two atoms different isotopes of the same element

Aloiza [94]

<span>the number of neutrons they have</span>

8 0

3 years ago

If two gases with pressures of 2 atm and 3 atm are mixed at a constant temperature, what will the total pressure be?

slamgirl [31]

If two gases with pressures of 2 atm and 3 atm are mixed at constant temperature, the total pressure will be the sum of the two pressures. Therefore the answer is D. 2 atm + 3 atm or 5 atm will be the total pressure of the gas mixture.

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3 years ago

Read 2 more answers

Which isotope will spontaneously decay and emit particles with a charge of +2?

VikaD [51]

Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$