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yan [13]
2 years ago
8

Write balanced equation for:

Chemistry
1 answer:
mario62 [17]2 years ago
4 0

Answer:

hmmm good luck

Explanation:

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Identify the heterogeneous mixtures from the list. Check all that apply. salad dressing hydrochloric acid solution orange juice
raketka [301]

Answer:

salad dressing

Explanation:

8 0
3 years ago
Read 2 more answers
What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?
vova2212 [387]
The volume of SO2 produced at 325k   is calculated as  below

calculate  the moles of SO2 produced  which  is calculated as follows

write the  reacting equation
K2SO3 +2 HCl = 2KCl +H2O+ SO2

find the   moles  of  HCl  used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles

by  use of mole ratio between  HCl to  SO2  which is  2:1 the moles of SO2 is therefore = 0.411 /2 =0.206  moles  of SO2

use the idea  gas  equation  to calculate the volume SO2
that is V=nRT/P  
where  n=0.206  moles
          R(gas constant) = 0.082 L.atm/ mol.k
         T=325 K
          P=1.35 atm

V=(0.206 moles x  0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2

3 0
2 years ago
How many atoms are in 35.1 g of sodium chloride (NaCl) ?
hoa [83]

Answer:

I believe that there are 70.2

Explanation:

There are 2 atoms in sodium chloride so I x 35.1 by 2 and got 70.2

8 0
3 years ago
Why was it important to establish the Clean Air Act?
deff fn [24]

Answer:

C.

Explanation:

The Clean Air Act was enacted in 1973 and brought to action in 1990. The act was passed to supervise air emissions to ensure clean air and atmosphere for people. The act was passed in the wake of premature deaths of hundred of thousands people. The act works with NAAQS to ensure safe and clean air for the safety of public health.

<u>From the given options the correct one is C. The Clean Air Act supervises the activities which emits air and any activities that is found to pollute the air will be labelled as illegal</u>.

Therefore, option C is correct.

5 0
3 years ago
Calculate the ph of the solution made by adding 0.50 mol of hobr and 0.30 mol of kobr to 1.00 l of water. the value of ka for ho
nikdorinn [45]
To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:

Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr] 

HOBr  = 0.50 M 
KOBr  = 0.30 M = OBr-

<span>     HOBr + H2O <-> H+ + OBr- </span>
<span>I     0.50        -              0          0.30 </span>
<span>C       -x                        x             x 
</span>---------------------------------------------
<span>E(0.50-x)                    x       (0.30+x) </span>

<span>Assuming that the value of  x is small as compared to 0.30 and 0.50 </span>

<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>

<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
3 0
3 years ago
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