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yan [13]
2 years ago
8

Write balanced equation for:

Chemistry
1 answer:
mario62 [17]2 years ago
4 0

Answer:

hmmm good luck

Explanation:

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What noble gas has the same electron configuration as the oxide ion?
Tems11 [23]
I love these type of questions :)

Final Answer: Neon
5 0
3 years ago
A drinking water plant adds 500 grams of fluoride to a water tank containing 500,000 liters of drinking water. what is the conce
nlexa [21]
Answer is: <span>concentration of fluoride in the water in parts-per-million is 1 ppm.
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5 0
3 years ago
Which of the following covalent bonds is the most polar?
Bezzdna [24]

Answer:

D.) H-O

Explanation:

Polarity is determined based on the difference in electronegativity of the atoms. The greater the difference, the more polar the bond. The general trend is that the atoms in the top-right corner of the periodic table are the most electronegative.

A.) is incorrect because H-H has no electronegativity difference, making it nonpolar.

B.) and C.) are incorrect because their electronegativity differences are not the greatest.

D.) is correct because the electronegativity difference between the H and O is the greatest.

5 0
2 years ago
What is the molarity of a 500.0 ml solution containing 0.75 moles of solute?
wariber [46]
M=mol/L
M=.75/.5
M=1.5
4 0
4 years ago
Give regents and mechanism
Kryger [21]

Answer:

Reagents: 1) BH_3 2) H_2_O2, OH^-

Mechanism: Hydroboration

Explanation:

In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.

The <u>first step</u> of this reaction is the addition of borane (BH_3) to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "BH_2-O-OH". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of OH^- on the O-BH_2 to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.

See figure 1

I hope it helps!

4 0
4 years ago
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