Answer: The space occupied by the gas at 400 torr and 
is 250 mL.
Explanation:
Given: 
= 250 mL, 
= 800 torr, 
, 
= 400 torr, 
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that space occupied by the gas at 400 torr and is 250 mL.
Answer:
C3 H6 Cl 3
Explanation:
C -24.2%
H - 4.0%
Cl - (100-24.2 - 4.0)=73.8 %
We can take 100g of the substance, then we have
C -24.2 g
H - 4.0 g
Cl - 73.8 g
Find the moles of these elements
C -24.2 g/12.0 g/mol =2.0 mol
H - 4.0 g/1.0 g/mol = 4. 0 mol
Cl - 73.8 g/ 35.5 g/mol = 2.1 mol
Ratio of these elements gives simplest formula of the substance
C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1
CH2Cl
Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol
Real molar mass = 150 g/mol
real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3
So, Real formula should be C3 H6 Cl 3.
Where are the following answers?
Answer:
2VO + 3Fe2O3 —> V2O5 + 6FeO
Explanation:
The skeletal equation for the reaction is given below below:
VO + Fe2O3 —> V2O5 + FeO
We can balance the equation above by doing the following:
There are 2 atoms of V on the right side and 1 atom on the left side. It can be balance by putting 2 in front of VO as shown below:
2VO + Fe2O3 —> V2O5 + FeO
Now, we have a total of 5 atoms of O on the left and 6 atoms on the right side. We can balance it by putting 3 in front of Fe2O3 and 6 in front of FeO as shown below:
2VO + 3Fe2O3 —> V2O5 + 6FeO
Now, we can see that the equation is balanced
