Answer:
0
Step-by-step explanation:
Let's define 3 areas:
- S = area of semicircle with radius 6 in (diameter AB)
- T = area of quarter circle with radius 6√2 in (radius AC)
- U = area of triangle ABC (side lengths 6√2)
The white space between the "moon" and the triangle has area ...
white = T - U
Then the area of the "moon" shape is ...
moon = S -white = S -(T -U) = S -T +U
The area we're asked to find is ...
moon - triangle = (S -T +U) -U = S -T
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The formula for the area of a circle of radius r is ...
A = πr²
So, ...
S = (1/2)π(6 in)² = 18π in²
and
T = (1/4)π(6√2 in)² = 18π in²
The difference in areas is S -T = (18π in²) -(18π in²) = 0.
There is no difference between the areas of the "moon" and the triangle.
5 days food for 150 students suggests there was 750 day rations
If there was 100 students this would last 750/100 = 7.5 days.
If it ran out after 4 days there were 750/4 = 187 students (187.5 not valid)
Dilation refers to a non rigid motion where a figure is transform and its image has the same form but a different size measure.
Dilation is define by the rule (x,y)-- (kx, ky) where k represents the scale factor.
On this exercise is given that a triangle with vertices (-2,1), (8,4), and (3,0) was dilated by a scale factor of four, and it is asked to find the vertices of the image of the triangle after the dilation occurred.
Pre-image Image
(-2,1) -- (-2*4,1*4) -- (-8,4)
(8,4) -- (8*4,4*4) -- (32,16)
(3,0) -- (3*4,0*4) -- (12,0)
The coordinates representing the vertices of the triangle's image are (-8,4), (32,16), and (12,0); meaning that the ordered pair which is not a coordinate for a point in the triangle's image is (2,1).