J = 14
J = 1/2S + 4 1/2
14 = 1/2S + 9/2....multiply everything by 2 to get rid of fractions
28 = S + 9
28 - 9 = S
19 = S
check...
14 = 1/2S + 9/2......S = 19
14 = 1/2(19) + 9/2
14 = 9 1/2 + 9/2
14 = 19/2+ 9/2
14 = 28/2
14 = 14 (correct)
so the sister is 19 <===
Answer:
The answer is<u> D.</u> h+3/j+6.
Step-by-step explanation:
Given:
The equation h + 3 = jk + 6k.
Now, to get the mathematical expression.

So, taking
common on R.H.S we get:

Then, dividing both sides by
we get:

Thus,

Therefore, the answer is D. h+3/j+6.
I might want to use the commutative property to change the order of the integers in the following sum before adding the given expression
"-80 + (-173)+(-20)"
As commutative property states that " Changing the order of addends does not change the sum" which means if we add 'a' to 'b' or 'b' to 'a', we will get the same answer.
Therefore, here if we add '-80' to '-173' or '-173' to '-80' , or if we add '-173' to '-20' or '-20' to '-173' , we will get the same answer.
Therefore, we might use commutative property to change the order the of integers in the following sum.
True.
E.g. (x-1)(x-2) versus 100(x-1)(x-2)
They have same roots of x= 1 or 2, but the second equation is 100 times stretching of the first one vertically
1)
m = 3√2√2
= 6
n = a
= 3√2
<u>Answer = </u><u> </u><u>D</u><u>)</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>,</u><u> </u><u>n</u><u> </u><u>=</u><u> </u><u>3</u><u>√</u><u>2</u>
2)
m = n = a
m = 3
n = 3
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>=</u><u> </u><u>A</u>