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Kazeer [188]
4 years ago
11

If a patient is diagnosed with a broken cheek, which bone is affected?

Biology
1 answer:
Andrews [41]4 years ago
5 0

Answer:

zygomatic bone or arch,

Explanation:

The part of the temporal bone of the skull that forms the prominence of the cheek. It is also known as the zygomatic bone or arch, the malar bone (creating confusion with the malar process of the maxilla), the cheek bone and the yoke bone.

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What is the function of lissome?
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FUNCTION: lysosomes provide an intracellular digestive system that allows the cell to digest the damaged cellular structures, the food particles that have been ingested by the cell and unwanted matter such as bacteria.it contain the hydrolytic enzyme that is capable of splitting an organic compound.
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4 years ago
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In humans there is a dominant allele (A) for the absence of moles; while the recessive allele (a) results in the presence of mol
Art [367]

Answer:

a. (p + q)^7 = p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7

b. i. 0.75

   ii. 0.000061

   iii. 0.012

   iv. 0.17

c. 0.67

Explanation:

a. The expansion of the binomial (p + q)7 would be such that:

(p + q)^7 = p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7

b. Both couples are heterozygous:

             Aa    x    Aa

         AA   Aa   Aa   aa

Since A is dominant over a,

probability of having mole (aa) = 1/4

probability of not having moles = 3/4

<em>Therefore, the probability of the first child not having moles </em>= 3/4 or 0.75

ii. Let the probability of not having mole = p and the probability of having mole = q. From the binomial expansion:

(p + q)^7 = p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7

<em>Probability that all of the children will have moles </em>= p^0q^7

since p = 3/4 and q = 1/4

p^0q^7 = (3/4)^0(1/4)^7 = 0.000061

iii. <em>Probability that the first two children will have no moles and the last five will have moles</em> = 21p^2q5

                       = 21(3/4)^2(1/4)^5

                         = 0.012

iv. <em>Probability that 4 will have no moles and 3 will have moles out of the 7 children</em> = 35p^4q^3

               = 35(3/4)^4(1/4)^3

                      = 0.17

c. <em>Probability that the child born without moles is a carrier of the a-allele  = probability of heterozygou</em>s.

From the cross in (b), the genotypes of those born without moles are AA and 2Aa. Therefore, the probability of not having moles and be Aa is:

      = 2/3 or 0.67

8 0
3 years ago
9. What part of the body covers the windpipe when you swallow?
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Answer:

epiglottis

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Answer:

The most appropriate answer would be option B.

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For example, they compared the DNA of lizard A and B whereas they compared the RNA of lizard B and C.

In addition, the mutation rates of different molecules (DNA and RNA) are different and thus, comparison of DNA in one set of organism and comparison of RNA in another set cannot be used as the basis for the conclusion.

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