Question

Find an equation of the line that passes through the given points. (Let x be the independent variable and y be the dependent variable.) (3, 9) and (4, 14)

Answer 1

Answer:

y=5x-6

Step-by-step explanation:

Hello

let´s see  , we have   P1(3,9) and P2(4.14)

first let's find its slope

$m=\frac{y2-y1}{x2-x1} = \frac{14-9}{4-3}$

$m=\frac{5}{1} \\m=5$

the slope is 5.

$y-y_{0} = m(x-x_{0} )\\\\using P1\\\\ y-9 = 5(x-3)\\\\y=5x-15+9\\\\y=5x-6$

where x is the independent variable and y is the dependent variable

Have a great day.