Please help me I need help

Find the value of x for which m is parallel to n A) 10 B) 12 C) 40 D) 52

Klio2033 [76]

Answer: $x=5\textdegree$

Explanation:

Since we have given that

line m and line n are parallel to each other,

So,

Corresponding angles are equal , as shown in the figure ,

According to question,

$19x\textdegree=180\textdegree-17x\textdegree\\\\19x\textdegree+17x\textdegree=180\\\\36x\textdegree=180\textdegree\\\\x=\frac{180}{36}\\\\x=5\textdegree$

Hence, $x=5\textdegree$

6 0

3 years ago

The length of the base of a rectangle is 6 less than 3 times the width. The perimeter of the rectangle is 52 inches. What is the

vivado [14]

Answer:

The rectangle has a width of 18 inches and a height length of 8 inches.

Step-by-step explanation:

The perimeter of a rectangle is described by the equation:

$p = 2w + 2l$

where l is width, h is height, and p is perimeter.

We're also told that the total perimeter is 52 inches.

We're also told that the length is six inches less than three times the width. We can express that as $w = 3l - 6$ .

We can plug that definition of w into the perimeter equation to find the length:

$p = 2w + 2l\\52 = 2(3l - 6) + 2 * l\\52 = 6l - 12 + 2l\\52 + 12 = 8l\\8l = 64\\l = 64/8\\l = 8$

Now we can take that and the given perimeter, and substitute those into the perimeter equation to find the width:

$p = 2w + 2l\\52 = 2w + 2(8)\\52 = 2w + 16\\36 = 2w\\w = 36 / 2\\w = 18$

So the width is 18

7 0

3 years ago

Graphically, a point is a solution to a system of two inequalities if and only if the point lies in the shaded region of the top

SOVA2 [1]

Answer:

lies in the shaded regions of both the top and bottom inequalities

Step-by-step explanation:

For a point to be a solution of two inequalities, it must lie in both solution sets. It ...

lies in the shaded regions of both the top and bottom inequalities

6 0

3 years ago

Read 2 more answers

Factor completely 4(x+1)^2/3 + 12(x+1)^-1/3

wolverine [178]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\
-------------------------------\\\\
%4(x+1)^2/3 + 12(x+1)^-1/3
4(x+1)^{\frac{2}{3}}+12(x+1)^{-\frac{1}{3}}\implies 4(x+1)^{\frac{2}{3}}+12\cfrac{1}{(x+1)^{\frac{1}{3}}}
\\\\\\$

$\bf 4(x+1)^{\frac{2}{3}}+\cfrac{12}{(x+1)^{\frac{1}{3}}}\impliedby \textit{so, our LCD is }(x+1)^{\frac{1}{3}}
\\\\\\
\cfrac{4(x+1)^{\frac{2}{3}}\cdot (x+1)^{\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)^{\frac{2}{3}+\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4(x+1)^{\frac{3}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4x+4+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4x+16}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+4)}{\sqrt[3]{x+1}}$

3 0

3 years ago

Read 2 more answers

Find slope plz!!!!ty

irga5000 [103]

Answer:

the slope is 3/5

Step-by-step explanation:

$\frac{10-7}{5-0} =\frac{3}{5}$

5 0

2 years ago