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Verizon [17]
3 years ago
7

What is the area of a circle with a radius of 1 foot?ооооplz helppp​

Mathematics
2 answers:
grandymaker [24]3 years ago
8 0

Answer:it should be c

Step-by-step explanation:

andriy [413]3 years ago
7 0

Answer:

third one

Step-by-step explanation:

area = pi * R^2 = pi * 1^2 = pi ft^2

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2n-5=11 what does n=
grandymaker [24]

Answer:

n = 8

Step-by-step explanation:

2n - 5 = 11

2n = 11 + 5

2n = 16

n = 16/2

n = 8

5 0
3 years ago
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Y^2=16 please helps me
zvonat [6]

Answer: y = 4

Step-by-step explanation:

4 * 4 = 16

3 0
3 years ago
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Can someone answer this
zmey [24]
Y=2/3x -4 . First, you look for the y when x=0. Then you try to find the best variation
5 0
3 years ago
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A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,
Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

As we know that,

The matrix is a Markov chain x_{k+1} = Hx_{k}

Let

The initial state vector be

x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]

∴ we get

x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]

Now,

x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]

∴ we get

x_{2} = \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

4 0
3 years ago
Which of the binomials below is a factor of this trinomial x^2+4x-60
trasher [3.6K]

Suppose x-6 is listed as a possible answer. That is zero if x = 6. So put x=6 into the original x^2 + 4x - 60 to get 6^2 + 4*6 - 60 = 36 + 24 -60 = 0. hence x-6 is a factor.

Answer (x-6)

on this hand :x-5 is not a factor, because plugging x=5 into does not work.

6 0
3 years ago
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