Ask question

Ask question

All categories

3 years ago

15

2n-5=11 what does n=

2 answers:

grandymaker [24]3 years ago

5 0

Answer:

n = 8

Step-by-step explanation:

2n - 5 = 11

2n = 11 + 5

2n = 16

n = 16/2

n = 8

slega [8]3 years ago

4 0

N = 14 will be your answer

You might be interested in

Question 5 of 10 Suppose that there were a negative correlation between the variables a and b. If bis 30 when a is 8, which of t

Fudgin [204]

Answer:

whats?

Step-by-step explanation:

8 0

3 years ago

What is the correct answer???

lapo4ka [179]

Answer:

Step-by-step explanation:

The given equation passes through the origin:

$y-0 = \frac{1}{4} (x-0) + 4$

The segment passes through the point (-2,6)

So the equation will become $(y-6) = \frac{1}{4} (x+2) +4$

3 0

3 years ago

What is the answer to 9=4y;y

Nitella [24]

Answer:

Y=9/4

Step-by-step explanation:

Divide both sides by 4

3 0

3 years ago

Mrs. Sloane has $500 to buy a video game console and some video games for her family. Including tax, the video game console cost

nexus9112 [7]

Answer:

1 console and 8 games because

Step-by-step explanation:

one console cost 280 and each game costs 25 so do 500-280=220 so, u have 220 dollars left basically. 220/25=8.8 so 8 games u can buy and the tax will be $20 because 0.8 * 25 = 20 so theres ur tax and u have to answer my question

6 0

3 years ago

Simplify: (Algebra)

kodGreya [7K]

Answer:

$2j-3o-5e+l-j+4o+6e= e+j+l+o$

$-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v$

$4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r$

$r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d$

$t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n$

$-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a$

$-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l$

$-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz$

$16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in$

$-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3$

$-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4$

$-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is$

$-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3$

$r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m$

$-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4$

$13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5$

$-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4$

Step-by-step explanation:

$a.\ 2j-3o-5e+l-j+4o+6e$

Collect Like Terms

$-5e+6e+2j-j+l+4o-3o$

$e+j+l+o$

Hence:

$2j-3o-5e+l-j+4o+6e= e+j+l+o$

$b.\ -7d+a+2v-i+8d-v+2i+d^2$

Collect Like Terms

$d^2+a+8d-7d-i+2i+2v-v$

$d^2+a+d+i+v$

Hence:

$-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v$

$c.\ 4a+12r-i+a^2-11r-3a+n+a^3$

Collect Like Terms

$a^3+a^2+4a-3a-i+n+12r-11r$

$a^3+a^2+a-i+n+r$

Hence:

$4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r$

$d.\ r^3-11a+12a-sh+2sh+i+d$

Evaluate like terms

$r^3+a+sh+i+d$

Hence:

$r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d$

$e.\ t^5+a-2a+2r-r+l-2l+a^4+3n-2n$

Evaluate like terms

$t^5-a+r-l+a^4+n$

Hence:

$t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n$

$f.\ -11i^2-r+2r+a^3-4d+3d-a$

Evaluate Like Terms

$-11i^2+r+a^3-d-a$

Hence:

$-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a$

$g.\ -9r+10r+a-s^3-2a+2s^3+u-l$

Collect Like Terms

$-9r+10r+a-2a+2s^3-s^3+u-l$

$r-a+s^3+u-l$

Hence:

$-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l$

$h.\ -4d+2a^3-a^3+5n+iz-4n$

Collect Like Terms

$-4d+2a^3-a^3+5n-4n+iz$

$-4d+a^3+n+iz$

Hence:

$-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz$

$i.\ 16a^5-2(l-y+y3)-a+d^2-d^3+in$

Open bracket

$16a^5-2l-2y+2y3-a+d^2-d^3+in$

Hence:

$16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in$

$j.\ -5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3$

Evaluate like terms

$-5z+e-y^5+n-a^5-l+l^3-i^3$

Hence:

$-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3$

$k.\ m-3m-a+2a-m^3-2m^5-a^3-d+l+i^4$

Evaluate like terms

$-2m+a-m^3-2m^5-a^3-d+l+i^4$

Hence:

$-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4$

$l.\ -4t^3+5t^3+3o-2o+2m-m-r^3-is+2is$

Evaluate like terms

$t^3+o+m-r^3+is$

Hence

$-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is$

$m.\ -5j+h-2h+4j-3a+6a-d^3$

Evaluate like terms

$-5j-h+4j+3a-d^3$

Hence:

$-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3$

$n.\ r^3-3u+2u-st+a^3-2a^3-5m+4m$

Evaluate like terms

$r^3-u-st-a^3-m$

Hence:

$r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m$

$o.\ -6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4$

Collect Like Terms

$-6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4$

$-6b^5+2a+h+18a^2-d^4-i^2-4r^4$

Hence:

$-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4$

$p.\ 13s^5-2o+5n^3-12s^5-6n^3+3o+a^5$

Collect Like Terms

$13s^5-12s^5-2o+3o+5n^3-6n^3+a^5$

$s^5+o-n^3+a^5$

Hence:

$13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5$

$q.\ -17m+16m-3u+r^3+2u-2r^3+a^4+d^4$

Collect Like Terms

$-17m+16m+2u-3u+r^3-2r^3+a^4+d^4$

$-m+-u-r^3+a^4+d^4$

Hence:

$-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4$

7 0

3 years ago