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Novosadov [1.4K]
3 years ago
13

4x + 1 = 2x – 5 can someone help me. Whoever gets it right gets it right gets brainliest

Mathematics
2 answers:
jeyben [28]3 years ago
4 0

<em>Hello Human!!</em>

<em>Your answer is below!!</em>

Step-by-step explanation:

Simplifying:

4x + 1 = 2x + -5

Reorder the terms:

1 + 4x = 2x + -5

Solving:

1 + 4x = -5 + 2x

Solving for variable x.

Move all terms containing x to the left, all other terms to the right.

Add -2x to each side of the equation.

1 + 4x + -2x = -5 + 2x + -2x

Combine like terms: 4x + -2x = 2x

1 + 2x = -5 + 2x + -2x

Combine like terms: 2x + -2x = 0

1 + 2x = -5 + 0

1 + 2x = -5

Add -1 to each side of the equation.

1 + -1 + 2x = -5 + -1

Combine like terms: 1 + -1 = 0

0 + 2x = -5 + -1

2x = -5 + -1

Combine like terms: -5 + -1 = -6

2x = -6

Divide each side by 2.

x = -3

Simplifying

x = -3

<em>So, Your answer is </em>x = -3.

<em>P.S </em><em>Tell me if this is wrong...</em>

<em />Good Luck!!<em />

<em>#</em>Be<em> </em>Bold<em />

<em># </em>Always<em> </em>Brainly!

_{Loserbrazts}

castortr0y [4]3 years ago
3 0

Answer:

x=-3

Step-by-step explanation:

subtract "2x" to "4x + 1" and that'll leave -5 by itself and leave 2x+1 on the left and -5 on the right then subtract -1 to -5 and it'll add up to -6 then after that you'd divide 2x to -6 and get -3 and it'll leave 'x' by itself so therefore X = -3

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Read 2 more answers
Find the area of ABC with vertices A(3,-6), B(5,-6), and C(7,–9).
stellarik [79]

Area of a triangle ABC with the given vertices is 3 square units.

Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).

<h3>What is the area of triangle formula in coordinate geometry?</h3>

In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.

Area of a triangle = \frac{1}{2} ( |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|)

Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)

Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)

= 1/2 (|3(3)+5(-3)+7(0)|)

= 1/2 (|(9-15)|)

= 1/2 × 6

= 3 square units

Therefore, area of a triangle ABC with the given vertices is 3 square units.

To learn more about the area of a area of triangle with vertices visit:

brainly.com/question/26633662.

#SPJ1

7 0
1 year ago
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