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kow [346]
3 years ago
13

Luis makes 3 free throws out of every 7 shots how many free throws will he make if he shoots 21 times

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0
3:7
x:21

9:21
the answer is he will make 9 free throws if he shoots 21 times.
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Pls i need help ASAP best answer gets brainlest
Pani-rosa [81]

Answer:

3^12

Step-by-step explanation:

Simplify the expression, 3^10/3^-2.

Next, solve for the sum. which will be 3^12.

Full answer is 531441

3 0
3 years ago
Read 2 more answers
The sum of the lengths of any two sides of a triangle must be greater than the third side. if a triangle has one side that is 8
BartSMP [9]

1st Side: 8

2nd Side: 2x - 1

3rd Side: x

(8) + (2x - 1) > x            (2x - 1) + x > 8                        (x) + (8) > 2x - 1

       2x + 7 > x                     3x - 1 > 8                                8  > x - 1

            2x > -7                         3x > 9                                9  > x

             x > -3.5 (disregard)       x > 3                                 x < 9

3rd Side: x  ⇒ (3 < x < 9)

2nd Side: 2x - 1 ⇒ 2(3) - 1 < x < 2(9) - 1   ⇒   5 < x < 17

Answer: the 3rd side must be between 3 and 9, the 2nd side must be between 5 and 17


6 0
4 years ago
X=a-2by(2) make y the subject
sladkih [1.3K]

Answer:

y = √{(a - x)/2b}

Step-by-step explanation:

x=a-2by²

2by² = a - x

divide through by 2b

y² = (a - x)/2b

y = √{(a - x)/2b}

3 0
4 years ago
In the cafeteria, 80 juice boxes were put out for breakfast. After breakfast, there were 20 juice boxes left.
olchik [2.2K]

Answer:

The ratio of juice boxes remaining to juice boxes drunk = 20 / 60 = 1/3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb,
NNADVOKAT [17]

Answer:

bbbb,

bbbg, bbgb, bgbb, gbbb,

bbgg, bgbg, bggb, gbgb, gbbg, ggbb,

bggg, gbgg, ggbg, gggb,

gggg

Step-by-step explanation:

3 children: bbb, bbg, bgb, gbb, bgg, gbg, ggb, ggg

4 children: bbbb, bbbg, bbgb, bgbb, gbbb, bbgg, bgbg, bggb, gbgb, ggbb, bggg, gbgg, ggbg, gggb, gggg

You need to take a methodological approach;

The 2 easiest are the possibility of all boys and all girls;

Then consider 3 boys and 1 girl:

bbbg, bbgb, bgbb, gbbb

Then 2 boys and 2 girls:

bbgg, bgbg, bggb, gbgb, gbbg, ggbb

Lastly, 1 boy and 3 girls:

bggg, gbgg, ggbg, gggb

In total, there are 16 possibilities

P.S. interesting to note is that the number of possibilities here follows the pattern of Pascal's triangle:

       1

     1   1

   1  2  1

 1  3  3  1

1  4  6  4  1

The last row is relevant here;

There is 1 possibility where there are 4 boys;

There are 4 possibilities (in terms of the order of birth) where there are 3 boys and 1 girl;

There are 6 possibilities where there are 2 boys and 2 girls

There are 4 possibilities where there is 1 boy and 3 girls;

There is 1 possibility where there are 4 girls;

The pattern ∴ is 1 4 6 4 1, as the 5th row of Pascal's triangle reads;

If your talking about 3 children, it would match the 4th row of Pascal's triangle;

So, 1 possibility of 3 boys;

3 possibilities of 2 boys and 1 girl;

3 possibilities of 1 boy and 2 girls;

And 1 possibility of 3 girls;

If your talking about 10 children, it would match the 11th row of Pascal's triangle.

(Maths can be so cool XD)

7 0
3 years ago
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