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harina [27]
2 years ago
5

A surfboard manufacturer makes small and large surfboards. The production process has three stages: assembly, finish, and inspec

tion. Each small surfboard requires 3 hours to assemble, 2 hours to finish, and 1 hour for inspection. Each large surfboard requires 4 hours to assemble, 3 hours to finish, and 1.5 hours for inspection. There are 140 hours available for assembly, 100 hours to finish, and 50 hours for inspection. The large surfboard makes $150 profit per board. The small surfboard makes $100 profit per board.Linear programming will be used to create the weekly production schedule.What would be a constraint for this problem if S
Mathematics
1 answer:
Brut [27]2 years ago
5 0

Answer:

z(max)  =  5000

x₁  =  2

x₂  = 32

Step-by-step explanation:

Time               Assemble       Finish       Inspection       Profit

Small   x₁               3                  2                  1                   100

Large   x₂              4                  3                  1,5                150

Availablity          140              100                50

Objective function:

z  =  100*x₁   +   150*x₂   to maximize

Subject to:

First constraint assembly capacity 140 hours

3*x₁  +  4*x₂   ≤  140

Second constraint finishing capacity 100 hours

2*x₁  + 3*x₂   ≤  100

Third constraint inspection capacity   50 hours

x₁  +  1,5*x₂    ≤  50

Model:

z  =  100*x₁   +   150*x₂   to maximize

Subject to:

3*x₁  +  4*x₂   ≤  140

2*x₁  + 3*x₂   ≤  100

x₁  +  1,5*x₂    ≤  50

General constraints    x₁  ≥  0    x₂  ≥  0  and integers

With the use of AtomZmath.com (online solver)

After 6 iterations the solution is:

z(max)  =  5000

x₁  =  2

x₂  = 32

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5 0
3 years ago
Use synthetic division find the product of ( 2x+3) and (x2-5x+6)​
alexgriva [62]

Answer:

8

x

3

+

2

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−

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Explanation:

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2

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(

4

x

2

−

5

x

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6

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Now let's distribute this piece by piece:

(

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(

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=

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x

3

(

2

x

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(

−

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2

(

2

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(

6

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=

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x

(

3

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(

4

x

2

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12

x

2

(

3

)

(

−

5

x

)

=

−

15

x

(

3

)

(

6

)

=

18

And now we add them all up (I'm going to group terms in the adding):

8

x

3

−

10

x

2

+

12

x

2

+

12

x

−

15

x

+

18

And now simplify:

8

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3

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2

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Step-by-step explanation:

6 0
3 years ago
Please answer!!!! please!!!!!!
olga55 [171]

The problem here is:  Too many words.

If you boil the problem down to the bare facts, the question is:

             "$210 is 15% of what number ?"

I'm pretty sure you can take it from there,
but here's the rest of it anyway:

                                                $210  =  15% of (March amount)

                                                $210  =  0.15 x (March amount)

Divide each side by  0.15 :     $1400 = March amount .

Check:
1400 + 210 =  1610
1.15 x 1400 = 1610                                      yay!
5 0
3 years ago
Una página de plástico diseñada para guardar cromos puede contener hasta 9 cartas. ¿Cuántas páginas se necesitarán para almacena
adelina 88 [10]

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.´

<h3>¿Cuántas páginas se necesitarán para almacenar 517 tarjetas? </h3>

Sabemos que cada página puede almacenar hasta 9 cartas.

Entonces queremos ver cuantos grupos de 9 cartas hay en el conjunto de 517, para ver esto tomamos el cociente entre 517 y 9.

N = 517/9  = 57.44

Y no podemos tener un numero racional, así que debemos redondear al proximo número entero, que es 58.

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.

Sí quieres aprender más sobre cocientes:

brainly.com/question/3493733

#SPJ1

8 0
10 months ago
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