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Yuliya22 [10]
2 years ago
11

Find the slope using the following points: (20,-10)(6,-20)

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0

   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

    <em>Find the slope using the following points:</em>

<em>         (20, -10) (6, -20)</em>

<em />

<em />\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

Use the slope formula:-

                    \LARGE\text{$\displaystyle\frac{y_2-y_1}{x_2-x_1}$}

Replace letters with numbers as follows:-

                             \Large\text{$\displaystyle\frac{-20-(-10)}{6-20}$}

On simplification,

                                  \Large\text{$\displaystyle\frac{-20+10}{-14}$}

On further simplification,

                                        \Large\text{$\displaystyle\frac{-10}{-14}$}

Reducing the fraction,

                               \large\text{$\displaystyle\frac{10}{14}$}

               \large\text{$\displaystyle\frac{5}{7}$}\leftarrow\:slope

<h3>Good luck with your studies.</h3>

\rule{300}{1}

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The volume of a cube is 8000 cubic feet, what is the area of one of its faces?
eimsori [14]

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Simplify: –3(x – 5) – 8(y + 2) + (–3)(6 – 4b)
Paha777 [63]
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Second, simplify. / Your problem should look like: -3 (x - 5) - 8 (y + 2) - 3 (b - 4b)
Third, expand your problem. / Your problem should look like: -3x + 15 - 8y - 16 - 18 + 12b
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Read 2 more answers
Find the vertex of the graph of the function.
lapo4ka [179]

Answer: The correct options are  (1) (5,10), (2) (3,-3), (3) x = -1, (4) y=(x+2)^2+3, (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

f(x)=a(x-h)^2+k        .....(1)

Where,  (h,k) is the vertex of the parabola.

(1)

The given equation is,

f(x)=(x-5)^2+10

Comparing this equation with equation (1),we get,

h=5 and k=10

Therefore, the vertex of the graph is (5,10) and the fourth option is correct.

(2)

The given equation is,

f(x)=3x^2-18x+24

f(x)=3(x^2-6x)+24

To make perfect square add (\frac{b}{2a})^2, i.e., 9. Since there is factor 3 outside the parentheses, so subtract three times of 9.

f(x)=3(x^2-6x+9)+24-3\times 9

f(x)=3(x-3)^2-3

Comparing this equation with equation (1),we get,

h=3 and k=-3

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

(3)

The given equation is

f(x)=4x^2+8x+7

f(x)=4(x^2+2x)+7

To make perfect square add (\frac{b}{2a})^2, i.e., 1. Since there is factor 4 outside the parentheses, so subtract three times of 1.

f(x)=4(x^2+2x+1)+7-4

f(x)=4(x+1)^2+3

Comparing this equation with equation (1),we get,

h=-1 and k=3

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

y=x^2+4x+7

To make perfect square add (\frac{b}{2a})^2, i.e., 2^2.

f(x)=x^2+4x+4+7-4

f(x)=x^2+4x+4+7-4

f(x)=(x+2)^2+3

Therefore, the correct option is  4.

(5)

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h=-16t^2+672t

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(6)

The given equation is,

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Use factoring method to find the factors of the equation.

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Equate each factor equal to 0.

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Therefore, the zeros of the given equation is 0, -1, 5 and the correct option is 2.

3 0
3 years ago
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