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3 years ago

9

If a leaf on the ground is 80 feet from the base of a tree, and the angle of elevation to the top of the tree from the leaf is 4

6 degrees. Then how tall is the tree?

2 answers:

rusak2 [61]3 years ago

6 0

Answer:

82.8424 feet

Step-by-step explanation:

The leaf, the base of the tree and the top of the tree form a triangle.

The adjacent cathetus to the 46 degrees angle is 80 feet. The opposite cathetus to the 46 degrees angle is the tree height that we want to know. So, using the relation between the opposite cathetus and the adjacent cathetus (so the tangent of the angle), we can find the tree height (h):

tan(46) = h/80 = 1.0355

h = 80*1.0355 = 82.8424 feet

coldgirl [10]3 years ago

5 0

Answer:

57.55 feet

Step-by-step explanation:

An image was attached to provide the necessary explanations.

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Tju [1.3M]

Step-by-step explanation:

1)......mean= sum of observations/ total observations

= 5.2+8.4+4.3+6.7+5.8/5= 6.08

median= n=5(odd)=n+1/2=6/2=3rdterm= 5.8( when arranged in ascending order).....

mode= 3median- 2meam= 3×5.8-2×6.08= 5.24

range=8.4-4.3=4.1(when done A.O)

2)......mean= -2-13-13-5-7/5= -8

median= 3rd term= -5.....(n=5..odd)(when done A.o)

mode=largest frequency= -13

range= -13-(-2) = -13+2= -11(A.O)

3).....mean= sum/no.= 8+6+13/2+17/2+15/2+7+8+11/2+7+8//10=7.2

median=n=10(even)

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mode= 8

range=8.5-5.5=3

median:==

(10/2)+(10/2+1)//2=5 term + 6term/2=7+7.5=14.5/2=7.25

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3 0

2 years ago

Find exact values for sin θ and tan θ if cos θ = -4/9 and tan θ > 0.

julsineya [31]

Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$cos(\theta)=-\frac{4}{9}$

substitute

$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

so

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

$cos(\theta)=-\frac{4}{9}$

substitute the given values

$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

3 0

3 years ago

A newspaper and three hot chocolates cost $7. Two newspapers and two hot chocolates cost $6. How much does one hot chocolate cos

pochemuha

Answer:

the cost of one hot chocolate is $2.

Step-by-step explanation:

Let x be the hot chocolate cost and y be the newspaper cost.

Given:

A newspaper and three hot chocolates cost $7

So, the equation is

$3x+y=7$ --------(1)

Two newspapers and two hot chocolates cost $6

So, the second equation is.

$2x+2y=6$ ---------(2)

Find one hot chocolate cost?

Solve equation 1 for y.

$3x+y=7$

$y=7-3x$

Put y value in equation 2

$2x+2(7-3x)=6$

$2x+14-6x=6$

$14-4x=6$

$-4x=6-14$

$-4x=-8$

negative sign is cancelled both side.

$x=\frac{8}{4}$

$x=2$

Therefore, the cost of one hot chocolate is $2.

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3 years ago

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andrezito [222]

Answer:

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Step-by-step explanation:

To find the difference between the two numbers we will do:

7°C - (-5°C)

Subtracting a negative number is the same as simply adding, so we can rewrite the equation as:

7°C + 5°C = 12°C

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3 years ago

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Nana76 [90]

(-7,8)

Simplifying 2(x+7)^2+8
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2 years ago