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Zielflug [23.3K]
3 years ago
5

Find the side length of a square with the given area. 

Mathematics
1 answer:
Semmy [17]3 years ago
5 0
B 11 in will be your answer!!!
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I am really confused on this question and need help
Alisiya [41]
The lines are parallel (meaning they have the same slope) so there is no solution.  If the lines overlap then there is infinite solutions.  If the lines cross there is one solution.

The only way to have more than one solution but not infinite is if the graphs are something other than lines.
8 0
4 years ago
Read 2 more answers
In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8%
Brilliant_brown [7]

Answer:

1998= 30,000 students

Step-by-step explanation:

Giving the following information:

In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8% more than 1999, find the enrolment in 1998

<u>First, we need to determine the enrolment in 1999:</u>

1999= 36,612/1.08

1999= 33,900

<u>Now, we can find the enrolment in 1998:</u>

1998= 33,900/1.13

1998= 30,000

6 0
4 years ago
Last week at a gym, 120 people participated in a biking class. The number of people who ran on a treadmill was
DENIUS [597]

Answer:

180 people ran on the treadmill at the gym last week.

6 0
4 years ago
The points (-1,6) and (1,r) lie on a line with a slope 4. Find the missing coordinator r?
ohaa [14]

Answer:

r=14

Step-by-step explanation:

r-6/1-(-1)=4

r-6=8

Therefore, r=14

5 0
4 years ago
Read 2 more answers
The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
vagabundo [1.1K]

Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

8 0
4 years ago
Read 2 more answers
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