The moment of inertia of a spherical shell is I = mr²
If two spheres have the same moment of inertia, then
I₁ = I₂
m₁(r₁)² = m₂(r₂)²
Solve for the second mass:
m₂ = m₁ (r₁/r₂)²
Given m₁ = 1 kg, r₁ = 2 m, r₂ = 1m,
m₂ = (1 kg) (2 m / 1 m)² = 4 kg
Answer:
Step-by-step explanation:
y + 4 = -6(x - 7)
y + 4 = -6x + 42
y = -6x + 38
The equation is given as: v=by/3 but it is actually <span>v=bh/3
</span><span>
Ans, now, we need to solve this for variable h.
So, </span>v=bh/3
On cross multiplying, we get,
3 × v = bh
On dividing the complete equation by "b" we get,
(3×v) / b = (bh)/b
or (3×v) / b = h
Thus, the value of h is : 3v/b
Answer: 1/6
Step-by-step explanation:
1/2 divided by 3/1 turns into 1/2 x 1/3 and when multiplying numerators and denominators with each other, you get 1/6.
The area of the base is:
A = root ((s-a) * (s-b) * (s-c) * (s))
Where,
a, b, c: sides of the triangle
s = (a + b + c) / 2
We have then:
s = (9 + 9 + 9) / 2
s = 13.5
A = root ((13.5-9) * (13.5-9) * (13.5-9) * (13.5))
A = 35.07
Then, the surface area of the prism is:
S.A = 2 * A + 9h + 9h + 9h
Where,
h: height of the prism:
Substituting values:
421.2 = 2 * (35.07) + 9h + 9h + 9h
Clearing h:
27h = (421.2 - 2 * (35.07))
h = (421.2 - 2 * (35.07)) / (27)
h = 13
Answer:
the height of the box is:
h = 13 inches
