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3 years ago

Which of the following best classifies a quadrilateral with coordinates A(2,6), B(5, 1), C(10, 4), and D(7,9)?

Mathematics

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

a rhombus

Step-by-step explanation:

If you graph the problem, you can see the shape of the quadrilateral. I attached a picture of a graph below. I hope this helped you!! Have a great rest of your day.

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Pretty simple for sixth graders and up so plz help

Paha777 [63]

the answer is -17/1 or 17/-1

3 0

3 years ago

The mean number of automobiles entering a mountain tunnel per two-minute period is one. An excessive number of cars entering the

viva [34]

Answer:

A Poisson model seems reasonable for this problem, since we have the mean during the time interval.

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x)=\frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The mean number of automobiles entering a mountain tunnel per two-minute period is one.

This means that $\mu = 1$ .

For a Poisson model to be reasonable, we only need the mean during the time interval. So yes, a Poisson model seems reasonable for this problem.

Find the probability that the number of autos entering the tunnel during a two-minute period exceeds three.

We want to find $P(X>3)$

Either this number is less or equal to 3, or it exceeds 3. The sum of the probabilities is decimal 1. So:

$P(X \leq 3) + P(X > 3) = 1$

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1}*1^{0}}{(0)!} = 0.3679$

$P(X = 1) = \frac{e^{-1}*1^{1}}{(1)!} = 0.3679$

$P(X = 2) = \frac{e^{-1}*1^{2}}{(2)!} = 0.1839$

$P(X = 3) = \frac{e^{-1}*1^{3}}{(3)!} = 0.0613$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3679 + 0.3679 + 0.1839 + 0.0613 = 0.981$

Finally

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.981 = 0.019$

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

8 0

3 years ago

WILL UPVOTE

Viktor [21]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
The expression has a value that is equivalent to 5n + 13 when n=−5n=−5 is <span>4n + 8.
</span>
your question should accompanied by an image. I manage to check the image from other sources

8 0

3 years ago

Read 2 more answers

Sarah has 52 balloons;13 of the balloons are red, and 4 of the balloons have polka dots. Just 1 of the red balloons has polka do

blsea [12.9K]

Answer:

17/52

Step-by-step explanation:

red: 13/52

polka dots: 4/52

13 + 4 = 17 = 17/52

(p.s the "Just 1 of the red balloons has polka dots." was kinda to throw u off it doesn't actually matter)

8 0

3 years ago

Complete the equations.<br> 2 x 18 = 2 x 3 x __<br> 2 x 18 = __

enot [183]

Answer:

Step-by-step explanation:

2x18=36

2x3x6=36

36=36

6 0

3 years ago

Read 2 more answers