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3 years ago

solve for a and B. A. a=400/21, b = 580/21 B. a=400/21, b=20/21. C a=580/21, b=20/21. D a=20/21, b=580/21

Mathematics

1 answer:

Brut [27]3 years ago

5 0

Answer:

Step-by-step explanation:

21/29 = 20/b

b = 20*29/21 = 580/21

a^2 + 20^2 = (580/21)^2

a = 400/21

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vovangra [49]

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Step-by-step explanation:

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Harman [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \: 14.25 \: \% \: }}}}}$

Step-by-step explanation:

Given,

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From the definition,

$\boxed{ \sf{Amount = \: Principal + Interest}}$

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3 years ago

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

yaroslaw [1]

Answer:

The value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

$4x^2-3x+9=2x+1$

which could also be written as:

$4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0$

The quadratic formula for the quadratic equation of the type:

$ax^2+bx+c=0$ is given as:

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Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}$

Hence, the value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

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I think the answer is 9

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